我正在建立一个在线购物网站。我想为用户提供一个选项,他/她可以选择不同的送货地址: -
<input type="button" value="Same as billing address" style="color: #FFFFFF;" class="link-style" onclick="test();" />
<table cellpadding="20">
<tr>
<td >Name : * </td>
<td><input type="text" id="name" name="name" /></td>
</tr>
<tr>
<td>Contact Number : </td>
<td><input type="text" name="cno" id="cno" /></td>
</tr>
<tr>
<td>Address : * </td>
<td><input type="text" name="address "id="address" /></td>
</tr>
<tr>
<td>City : *</td>
<td><input type="text" name="city" id="city" /></td>
</tr>
<tr>
<td>State : * </td>
<td><input type="text" name="state" id="state" /></td>
</tr>
<tr>
<td>Country : *</td>
<td><input type="text" name="country" id="country" /></td>
</tr>
</table>
如果用户点击按钮,则禁用所有字段。否则他/她可以填写不同的送货地址。问题是我不想在这里使用表单。如何在会话或发布中将这些参数传递给jsp或servlet?我已经尝试过AJAX,但我无法正常使用它
function setValue() {
alert("hi");
var name = document.getElementById("name").value;
var cno = document.getElementById("cno").value;
var address = document.getElementById("address").value;
var city = document.getElementById("city").value;
var state = document.getElementById("state").value;
var country = document.getElementById("country").value;
var xmlhttp = new XMLHttpRequest();
xmlhttp.open("post", "test.jsp", true);
xmlhttp.setRequestHeader("Content-type", "application/x-www-form- urlencoded");
xmlhttp.send("name=" + name);
xmlhttp.send("cno=" + cno);
xmlhttp.send("address=" + address);
xmlhttp.send("city=" + city);
xmlhttp.send("state=" + state);
xmlhttp.send("country=" + country);
}
Test.jsp没有获取参数。
答案 0 :(得分:1)
您必须只调用xmlhttp.send
一次,这需要您连接请求参数。
xmlhttp.send("name="+name+"&cno="+cno+"&address="+address+"&city="+city+"&state=" + state + "&country="+country);
答案 1 :(得分:0)
尝试这样:
var inputParam='{"name":"'+name+'","cno":"'+cno+'","address":"'+address+'","city":"'+city+'","state":"'+state+'","country":"'+country+'"}';
$.ajax({
type: "POST",
url: your base_url,
data: {inputParam:inputParam,module :'your module name'},
dataType: "json",
async:false,
success: function(msg)
{
console.log(msg);
}
});