Question

我有两张桌子：

表1 ：activity history

activity id   activity date
1              10/12/13 
1              12/12/13
1              23/1/14
2              22/12/13
2              01/01/14
2              04/03/14

表2 ：activity log

activity id       activity done
1                 call sent to client
2                 client is not picking

我是否有一个SQL查询，它给我带来如下结果：

activity id  |   activity done           | latest date of activity

    1           call sent to client             23/1/14

    2           client is not picking           04/03/14

我被困在必须获取最新活动日期以及其他字段的地方。请帮忙。

Answer 1

你可以写这样的东西;

SELECT b.ActivityId, b.ActivityDone, MAX(a.ActivityDate) as 'ActivityDate' 
FROM Table2 b 
    INNER JOIN Table1 a ON b.ActivityId = a.ActivityId 
GROUP BY b.ActivityId, b.ActivityDone

Answer 2

 SELECT x.ActivityId, MAX(x.ActivityDate), y.ActivityDone 
    FROM Table2 y 
        INNER JOIN Table1 x ON y.ActivityId = x.ActivityId 
GROUP BY b.ActivityId, b.ActivityDone

Answer 3

试试这个

SELECT T2.ActivityID, T2.ActivityLog, MAX(CAST(T1.ActivityDate AS DAte)) AS 'ActivityDate' 
FROM Table2 T2 INNER JOIN Table1 T1 ON T2.ActivityId = T1.ActivityId 
GROUP BY T1.ActivityID,T2.ActivityID, T2.ActivityLog

<强> Fiddle Demo

<强> OP：

ACTIVITYID  ACTIVITYLOG            ACTIVITYDATE
1           call sent to client    2014-01-23
2           client is not picking  2014-03-04

sql查询日期获取联接

3 个答案: