Question

我正在处理一段话。我需要按字母顺序对段落中的单词进行排序，然后按反向频率对它们进行排序。当我的单词计数功能对通道进行排序时，它也计算空白空间。我做了一些修改，它仍然计算空字符串。我想知道是否还有其他方法可以做到这一点。我的代码是：

def build_map( in_file, word_map ):

    for line in in_file:

        # Splits each line at blank space and turns it into
        # a list.
        word_list = line.split()

        for word in word_list:
            if word!='':

                # Within the word_list, we are stripping empty space
                # on both sides of each word and also stripping any
                # punctuation on both side of each word in the list.
                # Then, it turns each word to the lower case to avoid
                # counting 'THE' and 'the' as two different words.
                word = word.strip().strip(string.punctuation).lower()#program revised
                add_word( word_map, word )

Answer 1

这应该让你朝着正确的方向前进，你需要处理它，可能是通过剥去句号和冒号，你可能想要将它全部小写。

passage = '''I am dealing with a passage. I am required to sort the words in the passage alphabetically and then sort them by reverse frequency. When my word count function sorts the passage, it counts empty space too. I did some modification and it still counts the empty spaces. I am wondering if there is any other way to do it. My codes are:'''

words = set(passage.split())

alpha_sort = sorted(words, key=str.lower)

frequency_sort = sorted(words, key=passage.count, reverse=True)

Answer 2

要从字符串列表中过滤空字符串，我会使用：

my_list = filter(None, my_list)

Answer 3

也许您正在寻找str.isspace()

Answer 4

而不是：

if word!='':

你应该使用：

if word.strip()!='':

因为第一个检查零长度字符串，并且您想要消除长度不为零的空格。剥离一个空格字符串将使其为零长度。

关于在字数中摆脱空白空间

4 个答案: