Question

我已为此problem on ACM-ICPC Live archive提交了许多用Java编写的解决方案。我严格遵循编写Java解决方案的所有说明。我甚至在我的IDE上安装了JDK 6，但我总是得到Runtime error，任何想法在这里抛出异常'因为我认为我处理了所有异常。

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.util.ArrayList;

class Main {

    BufferedReader read;
    BufferedWriter write;
    Integer D, N;
    String U, S;
    ArrayList<String> cryptex;

    public static void main(String[] args) {

        new Main().solve();

    }

    private void solve() {

        read = new BufferedReader(new InputStreamReader(System.in));
        write = new BufferedWriter(new OutputStreamWriter(System.out));

        process();

        try {
            read.close();
            write.flush();
            write.close();
        } catch (IOException ex) {
            return;
        }
    }

    private void process() {

        try {
            D = Integer.parseInt(read.readLine().trim());
        } catch (IOException ex) {
            return;
        }

        for (int i = 0; i < D; i++) {
            try {
                String[] params = read.readLine().trim().split("\\s+");
                if (params.length != 3) {
                    return;
                }

                N = Integer.parseInt(params[0]);
                U = params[1];
                S = params[2];

                cryptex = new ArrayList<String>(N);

                for (int j = 0; j < N; j++) {
                    cryptex.add(read.readLine().trim());
                }

                try {
                    write.write(U + " " + solveCase());
                } catch (Exception ex) {
                    return;
                }

                write.newLine();
                read.readLine();
            } catch (IOException ex) {
                return;
            }

        }
    }

    private String solveCase() throws Exception {
        Integer n = null, f = null, add = null;
        for (int i = 0; i < N; i++) {
            if (S.charAt(i) != '_') {
                n = cryptex.get(i).indexOf(S.charAt(i));
                f = cryptex.get(i).indexOf(U.charAt(i));
                add = n - f;
                break;
            }
        }
        if (n == null || f == null || add == null) {
            throw new Exception("Incorrect test case exception.");
        }
        char[] ret = S.toCharArray();
        for (int i = 0; i < N; i++) {
            f = cryptex.get(i).indexOf(U.charAt(i));
            n = (add + f + 26) % 26;
            ret[i] = cryptex.get(i).charAt(n);
        }

        return new String(ret);
    }

}

关于我可能做错什么的任何想法？

Answer 1

在process方法中，您可以致电

D = Integer.parseInt(read.readLine().trim());

这不是最佳选择。使用扫描仪。你的行看起来应该更像这样：

Scanner sc = new Scanner(System.in);
//...
try {
    D = sc.nextInt(); // Number of test cases
    N = sc.nextInt(); // Rings
    U = sc.next();    // Unlocking word
}
//...

另外，请注意，可能会有多个测试用例，因此process()或其他方法需要在for循环内。

ACM-ICPC Live Archive 3242上的运行时错误 - 达芬奇的Cryptex

1 个答案: