我的图片存储在Google应用引擎数据存储区中。我想检索它们并在我的应用程序中显示它们。这是我的应用程序的代码:
main.py
class FileUpload(Handler):
def post(self):
file_upload = self.request.POST.get("file", None)
file_name = file_upload.filename
image = Images(id=file_name, file_name=file_name, blob=file_upload.file.read())
image.put()
self.response.headers[b'Content-Type'] = mimetypes.guess_type(image.file_name)[0]
self.response.write(image.blob)
class ImgServe(Handler):
def get(self, resource):
image = ndb.Key('Images', resource).get()
self.response.headers[b'Content-Type'] = mimetypes.guess_type(image.file_name)[0]
self.response.write(image.blob)
class Blob(Handler):
def get(self):
self.render("blob.html")
class Template(Handler):
def get(self):
self.render('template.html')
app = webapp2.WSGIApplication([('/', MainPage),
('/signup', Register),
('/login', Login),
('/logout', Logout),
('/mp', MP),
(r'/file_upload', FileUpload),
('/blob', Blob),
(r'/img_serve/<resource:(.*)>', ImgServe),
('/template', Template)], debug=True)
blob.html
<!DOCTYPE HTML>
<html lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>Image Upload</title>
</head>
<body>
<form action="/file_upload" enctype="multipart/form-data" method="post">
<div><input type="file" name="file"/></div>
<div><input type="submit" value="Upload"></div>
</form>
</body>
</html>
template.html
<html>
<head>
<title>Template</title>
</head>
<body>
<img src="/img_serve/evs.jpeg" />
</body>
</html>
以下是我的数据库的屏幕截图:
但是,这是我在template.html上获得的输出:
我期待'evs.jpeg'显示在template.html上。我的代码似乎有什么问题?
答案 0 :(得分:0)
您没有义务自己提供图片。 Google可以为您完成这项工作:
请参阅:https://developers.google.com/appengine/docs/python/images/functions
get_serving_url(blob_key,size = None,crop = False,secure_url = None)
您只需传递已存储的blob_key,即可获取服务网址,以便在HTML模板中使用。
或者,您可以按照服务blob的文档:
见这里:https://developers.google.com/appengine/docs/python/blobstore/#Python_Complete_sample_application
class ServeHandler(blobstore_handlers.BlobstoreDownloadHandler):
def get(self, resource):
resource = str(urllib.unquote(resource))
blob_info = blobstore.BlobInfo.get(resource)
self.send_blob(blob_info)
也可以通过传入一个字符串来覆盖文件名:
self.send_blob(blob_info,save_as='evs.jpg')