Question

我有一个xml文件，如下所示。在其中我想选择节点中的值并将它们插入到单独的字典中。我的代码如下。当我迭代时，字典计数返回零。建议请。

 <EmployeeFinance>
    <EstateId>157</EstateId>
    <EmpPersonal_Id>494</EmpPersonal_Id>
    <NonStatDedct>
      <DeductedAmt NonStatID="106">5000</DeductedAmt>
      <DeductedAmt DeductionID="106">5000</DeductedAmt>
    </NonStatDedct>
 </EmployeeFinance>

 var query = from nm in xelement.Descendants("EmployeeFinance")
 where (int)nm.Element("EmpPersonal_Id") == empID
 select new NonStatDed_Breakdown
 {
     Nonst = nm.Element("NonStatDedct").Elements("DeductedAmt").Where(a => a.Attributes().Equals("NonStatID")).ToDictionary(a => (int)a.Attribute("NonStatID"), a => (double)a),
     Deduc = nm.Element("NonStatDedct").Elements("DeductedAmt").Where(a => a.Attributes().Equals("DeductionID")).ToDictionary(a => (int)a.Attribute("DeductionID"), a => (double)a)
 };
 var resultquery = query.SingleOrDefault();

当我检查resultquery.Nonst和resultquery.Deduc时，计数返回0.我不知道我做错了什么。

Answer 1

这条线没有意义：

a.Attributes().Equals("NonStatID")

您需要获取属性值并将其与实际值进行比较，而不是属性名称：

.Where(a => (int)a.Attribute("NonStatID") ==  statId)

或者，如果您要查找属性名称，则可以使用Any方法Where，如下所示：

.First(a => a.Attributes().Any(x => x.Name == "NonStatID"))

那么你的代码应该是这样的：

 var query = from nm in xelement.Descendants("EmployeeFinance")
     where (int)nm.Element("EmpPersonal_Id") == empID
     select new NonStatDed_Breakdown
     {
         Nonst = nm.Element("NonStatDedct")
                  .Elements("DeductedAmt")
                  .Where(a => a.Attributes().Any(x => x.Name == "NonStatID"))                   
                  .ToDictionary(a => (int)a.Attribute("NonStatID"), a => (double)a),

         Deduc = nm.Element("NonStatDedct") 
                 .Elements("DeductedAmt")
                 .Where(a => a.Attributes().Any(x => x.Name == "DeductionID"))       
                 .ToDictionary(a => (int)a.Attribute("DeductionID"), a => (double)a)
    };

从xml文件中选择一个字典

1 个答案: