Question

我有以下数组：

$data = array(
  "Between 'Fluent, spontaneous, almost effortless flow' and 'Communicates spontaneously and reasonably fluently even in longer complex speech'",
  "Between 'Good use of a fairly broad vocabulary range sometimes with gaps' and 'Good range of vocabulary used in their field and most general topics but with gaps'"
);

我试图将单引号的内容放入另一个数组中：

for($i = 0; $i < count($data); $i++){                      
    if(preg_match("/^Between/", $data[$i])){
        $pattern = "/(?:^|\s)'([^']*?)'(?:$|\s)/";
        $candos_split = preg_grep($pattern, $data[$i]);
    }
}

但是$ candos_split返回NULL，即使我已经测试了我的正则表达式，它也没有问题。我知道它一定是蠢事，但我看不出问题出在哪里。

Answer 1

preg_grep() greps数组，而不是字符串。您可能想要使用preg_match_all()代替：

$data = array(
  "Between 'Fluent, spontaneous, almost effortless flow' and 'Communicates spontaneously and reasonably fluently even in longer complex speech'",
  "Between 'Good use of a fairly broad vocabulary range sometimes with gaps' and 'Good range of vocabulary used in their field and most general topics but with gaps'"
);

$pattern = "/(?:^|\s)'([^']*?)'(?:$|\s)/";
$matches = array();
foreach($data as &$line) {                     
    if(preg_match_all($pattern, $line, $m))
        $matches = array_merge($matches, $m[1]);
}

print_r($matches)将返回：

Array
(
    [0] => Fluent, spontaneous, almost effortless flow
    [1] => Communicates spontaneously and reasonably fluently even in longer complex speech
    [2] => Good use of a fairly broad vocabulary range sometimes with gaps
    [3] => Good range of vocabulary used in their field and most general topics but with gaps
)

Answer 2

应该可以在一切匹配中使用它

编辑如果您使用换行符\n字符加入所有源数组元素以形成单个
然后你可以在那个字符串上调用match_all，你应该得到一个单独的数组所有不同的引用项目。

 # '/(?m)(?:^Between|(?!^)\G)[^\'\n]*[^\S\n]\'([^\'\n]*)\'(?=\s|$)/'

 (?m)                    # Multi line mode
 (?:
      ^ Between          # 'Between'
   |                     # or,
      (?! ^ )
      \G                 # Start at last match
 )
 [^'\n]*                 # Not ' nor newline
 [^\S\n]                 # Non - newline wsp     
 '
 ( [^'\n]* )             # (1)
 '
 (?= \s | $ )

preg_grep返回NULL

2 个答案: