Question

我必须使用console.log（data）函数;在我的JavaScript中，但它很有效。有人知道怎么做吗？我刚刚将我的问题编辑成了一些更多的信息最好的问候朱莉

    <script type="text/javascript">
  $(function() {
    $(".datepicker" ).datepicker({
      dateFormat: 'yy-mm-dd',
      onSelect: function(date, instance){

      },
    });

    $("input[name=endDate]").datepicker({
      dateFormat: 'yy-mm-dd',
      onSelect: function(date, instance){
        $.post( "../getHoursSQL", {start:$("#startDate").val(),end:$("#endDate").val()}, function( data ) {
            console.log(JSON.stringify(data));
          $( "#startresult" ).html( data );
        },'json');
      }
    });
  });
</script>
</head>
<body>
    <form method="post" id="myForm" action="../getHoursSQL">
    Start Date:
        <input type="text" name="startDate" class="datepicker"/><br/>                     
    End Date:
        <input type="text" name="endDate" class="datepicker"/><br/>
        <input type="submit"/>
    </form>
        <div id="startresult"></div>
        <div id="endresult"></div>
</body>

控制台打印： Console Print

我的Servlet：

import java.io.*;
import java.sql.*;
import java.text.SimpleDateFormat;
import javax.servlet.*;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.*;

@WebServlet("/getHoursSQL")
public class getHoursSQL extends HttpServlet{

    private static final long serialVersionUID = 1L;

    @Override
    protected void doGet(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        doPost(request, response);
    }

    public void doPost(HttpServletRequest req, HttpServletResponse res) 
        throws ServletException, IOException{

        String connectionURL = "jdbc:mysql://localhost/NekiWork";
        Connection connection=null;

        try {
            //Load database driver
            Class.forName("com.mysql.jdbc.Driver");
            //Connection to the database
            connection = DriverManager.getConnection(connectionURL, "root", ""); 
            //Getting the data from database

            String sql = "SELECT *, (Day_hours + (Day_minutes / 60)) AS Allday_hours FROM Workdata "
                    + " WHERE Date = ? AND Date = ? ";
            PreparedStatement pst = connection.prepareStatement(sql);

            SimpleDateFormat format = new SimpleDateFormat("yyyy-mm-dd");

            java.util.Date util_startDate = format.parse( req.getParameter("startDate") );  
            java.sql.Date sql_startDate = new java.sql.Date( util_startDate.getTime() );

            java.util.Date util_endDate = format.parse( req.getParameter("endDate") );      
            java.sql.Date sql_endDate = new java.sql.Date( util_endDate.getTime() );

                pst.setDate( 1, sql_startDate );
                pst.setDate(2, sql_endDate );
                System.out.println(req.getParameter("startDate"));                          
                System.out.println(req.getParameter("endDate"));

                //Show the result from database

                ResultSet rs = pst.executeQuery();

            float Allday_hours_sum = 0;
                while (rs.next()){                                      
                    Allday_hours_sum += rs.getFloat("Allday_hours"); 

                }   
                res.setContentType("text/html;charset=UTF-8");          
                res.getWriter().print(Allday_hours_sum); 

                pst.close();

        }
        catch(ClassNotFoundException e){

            System.out.println("Couldn't load database driver: " + e.getMessage());
        }
        catch(SQLException e){
            System.out.println("SQLException caught: " + e.getMessage());
        }
        catch (Exception e){
            e.printStackTrace();
        }
        finally {

            try {
                if (connection != null) connection.close();
            }
            catch (SQLException ignored){
                System.out.println(ignored);
            }
        }
    }
}

POST SERVLET控制台图像 enter image description here

Answer 1

暂时不要担心console.log。查看浏览器开发人员控制台中网络选项卡的响应选项卡。

检查getHoursSQL

返回的任何内容

顺便说一下，不应该getHoursSQL.php或类似的？

编辑：

在您的情况下

getHoursSQL.java

如何console.log（数据）;在javascript中

1 个答案: