Question

我正在努力解决一个问题，这个问题可能非常简单，但却无法推理和分析。我正在使用三种不同的XSD，然后使用XJC创建用于创建Web服务的java类。

Prvilege.xsd

<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns="http://xmlns.hishekha.org/type"
    targetNamespace="http://xmlns.hishekha.org/type"
    xmlns:xs="http://www.w3.org/2001/XMLSchema" 
    elementFormDefault="qualified"
    attributeFormDefault="unqualified">
    <xs:element name="Privilege" type="Privilege" />

    <xs:complexType name="Privilege">
        <xs:sequence>
            <xs:element name="Id" type="xs:int" />
            <xs:element name="Name" type="xs:string" />
        </xs:sequence>
    </xs:complexType>
</xs:schema>

Role.xsd

<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns="http://xmlns.hishekha.org/type"
    targetNamespace="http://xmlns.hishekha.org/type"
    xmlns:xs="http://www.w3.org/2001/XMLSchema" 
    xmlns:privilege="http://xmlns.hishekha.org/type"
    elementFormDefault="qualified"
    attributeFormDefault="unqualified">

    <xs:import schemaLocation="Privilege.xsd" namespace="http://xmlns.hishekha.org/type"  />
    <xs:element name="Role" type="Role" />
    <xs:complexType name="Role">
        <xs:sequence>
            <xs:element name="Id" type="xs:int" />
            <xs:element name="Name" type="xs:string" />
            <xs:element name="Privilege" type="privilege:Privilege" minOccurs="1" maxOccurs="unbounded" />
        </xs:sequence>
    </xs:complexType>

</xs:schema>

User.xsd

<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:u="http://xmlns.hishekha.org/type"
    targetNamespace="http://xmlns.hishekha.org/type" 
    xmlns:xs="http://www.w3.org/2001/XMLSchema" 
    xmlns:role="http://xmlns.hishekha.org/type"
    elementFormDefault="qualified"
    attributeFormDefault="unqualified">

    <xs:include schemaLocation="Role.xsd"  />

    <xs:element name="User" type="u:User" />

    <xs:complexType name="User">
        <xs:sequence>
            <xs:element name="Id" type="xs:int" />
            <xs:element name="Username" type="xs:string" />
            <xs:element name="FirstName" type="xs:string" />
            <xs:element name="LastName" type="xs:string" />
            <xs:element name="Email" type="xs:string" />
            <xs:element name="Birthdate" type="xs:date" />
            <xs:element name="Role" type="role:Role" />
            <xs:element name="IsAccountExpired" type="xs:boolean" />
            <xs:element name="IsAccountLocked" type="xs:boolean" />
            <xs:element name="IsAccountASLExpired" type="xs:boolean" />
            <xs:element name="IsAccountEnabled" type="xs:boolean" />
        </xs:sequence>
    </xs:complexType>       
</xs:schema>

到目前为止，如果我在pom.xml中使用以下maven插件comf调用mvn编译，它可以很好地生成类。

<plugin>
    <groupId>org.codehaus.mojo</groupId>
    <artifactId>jaxb2-maven-plugin</artifactId>
    <version>1.5</version>
    <executions>
        <execution>
            <goals>
                <goal>xjc</goal>
            </goals>
        </execution>
    </executions>
    <configuration>
        <clearOutputDir>false</clearOutputDir>
        <outputDirectory>src/main/java</outputDirectory>
        <schemaDirectory>src/main/webapp/schemas</schemaDirectory>
        <includes>**/*xsd</includes>
        <enableIntrospection>false</enableIntrospection>
    </configuration>
</plugin>

但是当我试图在其他具有不同名称空间的xsd中使用它时。

UserServiceOperations.xsd

<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns="http://xmlns.hishekha.org/services"
    targetNamespace="http://xmlns.hishekha.org/services"
    xmlns:xs="http://www.w3.org/2001/XMLSchema" 
    xmlns:u="http://xmlns.hishekha.org/type"
    elementFormDefault="qualified"
    attributeFormDefault="unqualified">

    <xs:import namespace="http://xmlns.hishekha.org/type" schemaLocation="User.xsd" />

    <xs:element name="UserResponseOutput">
        <xs:complexType>
            <xs:sequence>
                <xs:element name="User" type="u:User" />
            </xs:sequence>
        </xs:complexType>
    </xs:element>

</xs:schema>

（我正在为Web服务输入输出模式做）它开始抛出以下错误

[INFO] Generating source...
[INFO] parsing a schema...
[ERROR] file:/C:/Users/hishekha.ORADEV/WorkspaceJ2EE/SimpleServices/src/main/web
app/schemas/UserServiceOperations.xsd[14,45]
org.xml.sax.SAXParseException; systemId: file:/C:/Users/hishekha.ORADEV/Workspac
eJ2EE/SimpleServices/src/main/webapp/schemas/UserServiceOperations.xsd; lineNumb
er: 14; columnNumber: 45; src-resolve: Cannot resolve the name 'u:User' to a(n)
'type definition' component.
        at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAX
ParseException(ErrorHandlerWrapper.java:198)
        at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.error(Err
orHandlerWrapper.java:134)
        at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(
XMLErrorReporter.java:437)
        at com.sun.org.apache.xerces.internal.impl.xs.traversers.XSDHandler.repo
rtSchemaErr(XSDHandler.java:4162)
        at com.sun.org.apache.xerces.internal.impl.xs.traversers.XSDHandler.repo
rtSchemaError(XSDHandler.java:4145)
        at com.sun.org.apache.xerces.internal.impl.xs.traversers.XSDHandler.getG
lobalDecl(XSDHandler.java:1741)
        at com.sun.org.apache.xerces.internal.impl.xs.traversers.XSDElementTrave
rser.traverseNamedElement(XSDElementTraverser.java:405)
        at com.sun.org.apache.xerces.internal.impl.xs.traversers.XSDElementTrave
rser.traverseLocal(XSDElementTraverser.java:194)
        at com.sun.org.apache.xerces.internal.impl.xs.traversers.XSDHandler.trav
erseLocalElements(XSDHandler.java:3618)
        at com.sun.org.apache.xerces.internal.impl.xs.traversers.XSDHandler.pars
eSchema(XSDHandler.java:633)
        at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaLoader.loadSchema
(XMLSchemaLoader.java:616)
        at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaLoader.loadGramma
r(XMLSchemaLoader.java:574)
        at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaLoader.loadGramma
r(XMLSchemaLoader.java:540)
        at com.sun.org.apache.xerces.internal.jaxp.validation.XMLSchemaFactory.n
ewSchema(XMLSchemaFactory.java:252)
        at com.sun.tools.xjc.reader.xmlschema.parser.SchemaConstraintChecker.che
ck(SchemaConstraintChecker.java:101) ....

我想我做了一些简单的错误，但无法弄明白。请帮帮我们注意：所有xsd文件都在同一目录中。

Answer 1

问题不在UserServiceOperations.xsd。它正确导入User.xsd模式，这对于验证对合格User元素的引用是必要的。

问题出在Role.xsd。它与Privilege.xsd属于相同的命名空间，因此您不应该导入，而包括它（如你在User.xsd做过，包括Role.xsd）。

不

<xs:import schemaLocation="Privilege.xsd" namespace="http://xmlns.hishekha.org/type"  />

但

<xs:include schemaLocation="Privilege.xsd" />

如果您更改了这一行，则可以验证UserServiceOperations.xsd并使用xjc生成类。

xjc失败，多个xsd具有不同的命名空间

1 个答案: