Question

自从过去两天以来，我一直试图让lajvel 4中的ajax文件上传工作，现在我好运不前了。

我的jquery块

$(document).ready(function(){

$('#basicModuleImage').change(function () {
    sendFile(this.files[0]);
});

function sendFile(file) {

  $.ajax({
    type: 'post',
    url: '/upload',
    data: file,
    enctype: 'multipart/form-data',
    success: function (data) {
            alert(data);
    },
    processData: false,
    contentType: file.type
  });
}
 });

HTML块

 <form method="post" action="">
 <input type="file" id="basicModuleImage" name="basicModuleImage" />
 </form>

LARAVEL PHP阻止

Route::post('upload', function(){

return Response::json(array('a'=>var_dump(Input::all()),'b'=>var_dump($_FILES)));

});

我也尝试使用https://github.com/LPology/Simple-Ajax-Uploader，但这似乎是laravel的一个问题。

JSON响应返回a和b都为null。

Answer 1

密钥在你的ajax请求中。在控制器中，你可以做任何你想做的事。

var form = document.forms.namedItem("yourformname"); // high importance!, here you need change "yourformname" with the name of your form
var formdata = new FormData(form); // high importance!

$.ajax({
    async: true,
    type: "POST",
    dataType: "json", // or html if you want...
    contentType: false, // high importance!
    url: '{{ action('yourController@postMethod') }}', // you need change it.
    data: formdata, // high importance!
    processData: false, // high importance!
    success: function (data) {

        //do thing with data....

    },
    timeout: 10000
});

Answer 2

Actualy，你不能通过（基本）AJAX（XMLHttpRequest）发送文件。

你的斗士需要使用一些＆＃34; iframe＆＃34;上传者，或XMLHttpRequest2 我会选择XHR2 这是我与Laravel4一起使用的代码部分的复制粘贴，就像一个魅力

/**
 * Read selected files locally (HTML5 File API)
 */
var filesToUpload = null;

function handleFileSelect(event)
{
    var files = event.target.files || event.originalEvent.dataTransfer.files;
    // Itterate thru files (here I user Underscore.js function to do so).
    // Simply user 'for loop'.
    _.each(files, function(file) {
        filesToUpload.push(file);
    });
}

/**
 * Form submit
 */
function handleFormSubmit(event)
{
    event.preventDefault();

    var form = this,
        formData = new FormData(form);  // This will take all the data from current form and turn then into FormData

    // Prevent multiple submisions
    if ($(form).data('loading') === true) {
        return;
    }
    $(form).data('loading', true);

    // Add selected files to FormData which will be sent
    if (filesToUpload) {
        _.each(filesToUpload, function(file){
            formData.append('cover[]', file);
        });        
    }

    $.ajax({
        type: "POST",
        url: 'url/to/controller/action',
        data: formData,
        processData: false,
        contentType: false,
        success: function(response)
        {
            // handle response
        },
        complete: function()
        {
            // Allow form to be submited again
            $(form).data('loading', false);
        },
        dataType: 'json'
    });
}

/**
 * Register events
 */
$('#file-input').on('change', handleFileSelect);
$('form').on('submit', handleFormSubmit);

Answer 3

尝试使用FormData()

$(document).ready(function () {

    $('#basicModuleImage').change(function () {
        sendFile(new FormData($('form')[0]));
    });

    function sendFile(file) {
        alert(file.type);
        $.ajax({
            type: 'post',
            url: '/upload',
            data: file,
            success: function (data) {
                alert(data);
            },
            processData: false,
            contentType: false
        });
    }
});

在laravel中上传AJAX文件

3 个答案: