假设我正在使用此代码将String(包含数字)转换为字符数组,我想将其转换为数字数组(int)。
(然后我想为另一个数字字符串执行此操作,并添加两个int数组以提供另外一个添加的int数组。)
我该怎么办?
import java.util.Scanner;
public class stringHundredDigitArray {
/**
* @param args
*/
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Enter the number: ");
String num1 = in.nextLine();
char[] num1CharArray = num1.toCharArray();
//for (int i = 0; i < num1CharArray.length; i++){
//System.out.print(" "+num1CharArray[i]);
//}
int[] num1intarray = new int[num1CharArray.length];
for (int i = 0; i < num1CharArray.length; i++){
num1intarray[i] = num1CharArray[i];
}
for (int i = 0; i < num1intarray.length; i++){ //this code prints presumably the ascii values of the number characters, not the numbers themselves. This is the problem.
System.out.print(" "+num1intarray[i]);
}
}
}
我真的必须拆分字符串,最好是一组可添加的数据类型。
答案 0 :(得分:2)
尝试Character.getNumericValue(char);
这个:
for (int i = 0; i < num1CharArray.length; i++){
num1intarray[i] = Character.getNumericValue(num1CharArray[i]);
}
答案 1 :(得分:1)
Try This :
int[] num1intarray = new int[num1CharArray.length];
for (int i = 0; i < num1CharArray.length; i++)
{
num1intarray[i]=Integer.parseInt(""+num1CharArray[i]);
System.out.print(num1intarray[i]);
}
答案 2 :(得分:0)
简短而简单的解决方案!
int[] result = new int[charArray.length];
Arrays.setAll(result, i -> Character.getNumericValue(charArray[i]));