我使用twitter4j REST API使用其推文ID检索特定的推文。我的代码如下。我可以下载推文，但它不是原始的JSON格式。使用相同的推文ID从https://dev.twitter.com/console获取的原始JSON格式不同 twitter4j。请帮帮我，如何获取实际的JSON文件。谢谢！
使用tweet4j重新发送推文的代码
package org.hi.hello;
import twitter4j.*;
import twitter4j.auth.AccessToken;
import twitter4j.json.DataObjectFactory;
import java.io.IOException;
public class TweetUsingTwitter4jExample {
public static void main(String[] args) throws IOException, TwitterException {
//Your Twitter App's Consumer Key
String consumerKey = "Zi03QNQ***9FVBRol0P2Kw";
//Your Twitter App's Consumer Secret
String consumerSecret = "sHKCBKeMD71jBUqA1J3dGDIsnQgw********";
//Your Twitter Access Token
String accessToken = "2383034234-reX0iWmtgUAaLdvCx1*******MvV4ItRwcJqytX";
//Your Twitter Access Token Secret
String accessTokenSecret = "aFn216CcmSmUTJjmrC9*****bz53hYUjIf7GqSeh90K";
//Instantiate a re-usable and thread-safe factory
TwitterFactory twitterFactory = new TwitterFactory();
//Instantiate a new Twitter instance
Twitter twitter = twitterFactory.getInstance();
//setup OAuth Consumer Credentials
twitter.setOAuthConsumer(consumerKey, consumerSecret);
//setup OAuth Access Token
twitter.setOAuthAccessToken(new AccessToken(accessToken, accessTokenSecret));
Status s = twitter.showStatus(Long.parseLong("126417285559762944"));
System.out.println(s.toString());
}
}
输出
StatusJSONImpl{createdAt=Wed Oct 19 03:30:04 IST 2011, id=126417285559762944, text='RT @Jewelz2611 @mashable @apple, iphones r 2 expensive. Most went w/ htc/galaxy. No customer loyalty w/phone comp..', source='<a href="http://geekking.in" rel="nofollow">_GeekKing</a>', isTruncated=false, inReplyToStatusId=-1, inReplyToUserId=-1, isFavorited=false, isRetweeted=false, favoriteCount=0, inReplyToScreenName='null', geoLocation=null, place=null, retweetCount=0, isPossiblySensitive=false, isoLanguageCode='null', lang='en', contributorsIDs=[], retweetedStatus=null, userMentionEntities=[UserMentionEntityJSONImpl{name='Jewelz', screenName='Jewelz2611', id=18176023}, UserMentionEntityJSONImpl{name='Mashable', screenName='mashable', id=972651}, UserMentionEntityJSONImpl{name='@apple', screenName='Apple', id=380749300}], urlEntities=[], hashtagEntities=[], mediaEntities=[], symbolEntities=[], currentUserRetweetId=-1, user=UserJSONImpl{id=20256514, name='PunjabiGeek', screenName='_GeekKing', location='India', description='Tech Geek, Gadgets fan, RC Fan,', isContributorsEnabled=false, profileImageUrl='http://pbs.twimg.com/profile_images/442731191255314432/8Li7PQCN_normal.png', profileImageUrlHttps='https://pbs.twimg.com/profile_images/442731191255314432/8Li7PQCN_normal.png', url='null', isProtected=false, followersCount=1069, status=null, profileBackgroundColor='000000', profileTextColor='000000', profileLinkColor='CC3300', profileSidebarFillColor='F7DA93', profileSidebarBorderColor='FFFFFF', profileUseBackgroundImage=true, showAllInlineMedia=false, friendsCount=933, createdAt=Fri Feb 06 23:35:47 IST 2009, favouritesCount=37, utcOffset=19800, timeZone='New Delhi', profileBackgroundImageUrl='http://pbs.twimg.com/profile_background_images/131659776/twitter.jpg', profileBackgroundImageUrlHttps='https://pbs.twimg.com/profile_background_images/131659776/twitter.jpg', profileBackgroundTiled=false, lang='en', statusesCount=26455, isGeoEnabled=false, isVerified=false, translator=false, listedCount=46, isFollowRequestSent=false}}
我使用以下网址https://dev.twitter.com/console从https://api.twitter.com/1.1/statuses/show/126417285559762944.json获得的内容：{{3}}
{
"created_at": "Tue Oct 18 22:00:04 +0000 2011",
"id": 126417285559762940,
"id_str": "126417285559762944",
"text": "RT @Jewelz2611 @mashable @apple, iphones r 2 expensive. Most went w/ htc/galaxy. No customer loyalty w/phone comp..",
"source": "<a href="http://geekking.in" rel="nofollow">_GeekKing</a>",
"truncated": false,
"in_reply_to_status_id": null,
"in_reply_to_status_id_str": null,
"in_reply_to_user_id": null,
"in_reply_to_user_id_str": null,
"in_reply_to_screen_name": null,
"user": {
"id": 20256514,
"id_str": "20256514",
"name": "PunjabiGeek",
"screen_name": "_GeekKing",
"location": "India",
"description": "Tech Geek, Gadgets fan, RC Fan,",
"url": null,
"entities": {
"description": {
"urls": []
}
},
"protected": false,
"followers_count": 1069,
"friends_count": 933,
"listed_count": 47,
"created_at": "Fri Feb 06 18:05:47 +0000 2009",
"favourites_count": 37,
"utc_offset": 19800,
"time_zone": "New Delhi",
"geo_enabled": false,
"verified": false,
"statuses_count": 26453,
"lang": "en",
"contributors_enabled": false,
"is_translator": false,
"is_translation_enabled": false,
"profile_background_color": "000000",
"profile_background_image_url": "http://pbs.twimg.com/profile_background_images/131659776/twitter.jpg",
"profile_background_image_url_https": "https://pbs.twimg.com/profile_background_images/131659776/twitter.jpg",
"profile_background_tile": false,
"profile_image_url": "http://pbs.twimg.com/profile_images/442731191255314432/8Li7PQCN_normal.png",
"profile_image_url_https": "https://pbs.twimg.com/profile_images/442731191255314432/8Li7PQCN_normal.png",
"profile_link_color": "CC3300",
"profile_sidebar_border_color": "FFFFFF",
"profile_sidebar_fill_color": "F7DA93",
"profile_text_color": "000000",
"profile_use_background_image": true,
"default_profile": false,
"default_profile_image": false,
"following": false,
"follow_request_sent": false,
"notifications": false
},
"geo": null,
"coordinates": null,
"place": null,
"contributors": null,
"retweet_count": 0,
"favorite_count": 0,
"entities": {
"hashtags": [],
"symbols": [],
"urls": [],
"user_mentions": [
{
"screen_name": "Jewelz2611",
"name": "Jewelz",
"id": 18176023,
"id_str": "18176023",
"indices": [
3,
14
]
},
{
"screen_name": "mashable",
"name": "Mashable",
"id": 972651,
"id_str": "972651",
"indices": [
15,
24
]
},
{
"screen_name": "Apple",
"name": "@apple",
"id": 380749300,
"id_str": "380749300",
"indices": [
25,
31
]
}
]
},
"favorited": false,
"retweeted": false,
"lang": "en"
}
答案 0 :(得分：3)
尝试将状态对象转换为自己为我工作的JSON 这是使用gson的实用方法
public static String copyToJsonString(Object modelObject ){
String data=null;
try {
Gson gson= new Gson();
data=gson.toJson(modelObject);
return data;
} catch (Exception e) {
e.printStackTrace();
}
}