我想从0-50获得罗马数字。我只是在文本框上写下整数，然后按下按钮，我想在标签中加入罗马格式。
我已经编写了代码，它在0-50个数字中运行良好。
但是，我认为我所拥有的解决方案并非最佳。
任何人都可以帮助我，我怎样才能让它更优化。
int number = Convert.ToInt32( tb_input.Text);
StringBuilder sb = new StringBuilder();
sb= IntToRoman(number, sb);
Label1.Text =sb.ToString();
public StringBuilder IntToRoman(int number, StringBuilder sb)
{
int flag = 0;
if (number >= 50 && flag==0)
{
sb.Append("L");
IntToRoman(number - 50, sb);
flag = 1;
}
if (number >= 10 && flag == 0)
{
sb.Append("X");
IntToRoman(number - 10, sb);
flag = 1;
}
if (number >= 9 && flag == 0)
{
sb.Append("IX");
IntToRoman(number - 9, sb);
flag = 1;
}
if (number >= 5 && flag == 0)
{
sb.Append("V");
IntToRoman(number - 5, sb);
flag = 1;
}
if (number >= 4 && flag == 0)
{
sb.Append("IV-");
IntToRoman(number - 4, sb);
flag = 1;
}
if (number >= 1 && flag == 0)
{
sb.Append("I");
IntToRoman(number - 1, sb);
flag = 1;
}
if (number ==0)
{
return sb;
}
return sb;
}
答案 0 :(得分：3)
非常简单的代码，适用于任何数字......
public static List<string> romanNumerals = new List<string>() { "M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I" };
public static List<int> numerals = new List<int>() { 1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1 };
public static string ToRomanNumeral(int number)
{
var romanNumeral = string.Empty;
while (number > 0)
{
// find biggest numeral that is less than equal to number
var index = numerals.FindIndex(x => x <= number);
// subtract it's value from your number
number -= numerals[index];
// tack it onto the end of your roman numeral
romanNumeral += romanNumerals[index];
}
return romanNumeral;
}
...用法
ToRomanNumeral(58) = 'LVIII'
ToRomanNumeral(2014) = 'MMXIV'
答案 1 :(得分：2)
试试这个：
它适用于数字1-3999;）如果您需要更多数字，您可以适应您的需要;）
public StringBuilder IntToRoman(int number, StringBuilder sb)
{
string line = number.ToString();
string[] numbers = { "I", "II", "III", "IV", "V", "VI", "VII", "VIII", "IX", "X", "XX", "XXX", "XL", "L", "LX", "LXX", "LXXX", "XC", "C", "CC", "CCC", "CD", "D", "DC", "DCC", "DCCC", "CM", "M", "MM", "MMM" };
int a = 1;
for (int i = line.Length - 1; i >= 0; i--)
{
string t = line.Substring(i, 1);
int t1 = int.Parse(t) * a;
if (t1 < 10 && t1 > 0)
sb.Insert(0, numbers[t1 - 1]);
if (t1 >= 10 && t1 < 100)
sb.Insert(0, numbers[9 + (int.Parse(t) - 1)]);
if (t1 >= 100 && t1 < 1000)
sb.Insert(0, numbers[18 + (int.Parse(t) - 1)]);
if (t1 >= 1000)
sb.Insert(0, numbers[27 + (int.Parse(t) - 1)]);
a *= 10;
}
Console.WriteLine(sb.ToString());
}
;）我希望这有效 这里的帖子在我的博客中有解释：
答案 2 :(得分：1)
这对我很有用：
Func<int, string> toRoman = x =>
{
var numerals = new []
{
new { text = "L", value = 50, },
new { text = "XL", value = 40, },
new { text = "X", value = 10, },
new { text = "IX", value = 9, },
new { text = "V", value = 5, },
new { text = "IV", value = 4, },
new { text = "I", value = 1, },
};
return
numerals.Aggregate(new { text = "", value = x }, (a, n) =>
{
var text = a.text;
var value = a.value;
while (value >= n.value)
{
text += n.text;
value -= n.value;
}
return new { text, value };
}).text;
};
例如：
toRoman(49) == "XLIX"
toRoman(73) == "LXXIII"
toRoman(8) == "VIII"
我认为使用StringBuilder几乎没有意义，因为所涉及的值不太可能通过使用字符串连接来解决重大性能问题。如果StringBuilder被认为是重要的，那么加入{{1}}并不困难。
答案 3 :(得分：0)
using Microsoft.VisualBasic;
using System;
using System.Collections;
using System.Collections.Generic;
using System.Data;
using System.Diagnostics;
public class Form1
{
int[] indx = {
1,
2,
3,
4,
5,
10,
50,
100,
500,
1000
// initialize array of integers
};
string[] row = {
"I",
"II",
"III",
"IV",
"V",
"X",
"L",
"C",
"D",
"M"
//Carasponding roman letters in for the numbers in the array
};
// integer to indicate the position index for link two arrays
int limit = 9;
//string to store output
string output = "";
private void Button1_Click(System.Object sender, System.EventArgs e)
{
int num = 0;
// stores the input
output = "";
// clear output before processing
num = Convert.ToInt32(txt1.Text);
// get integer value from the textbox
//Loop until the value became 0
while (num > 0) {
num = find(num);
//call function for processing
}
txt2.Text = output;
// display the output in text2
}
public int find(int Num)
{
int i = 0;
// loop variable initialized with 0
//Loop until the indx(i).value greater than or equal to num
while (indx(i) <= Num) {
i += 1;
}
// detemine the value of limit depends on the itetration
if (i != 0) {
limit = i - 1;
} else {
limit = 0;
}
output = output + row(limit);
//row(limit) is appended with the output
Num = Num - indx(limit);
// calculate next num value
return Num;
//return num value for next itetration
}
}
答案 4 :(得分：0)
如果您只是在寻找一种将整数转换为0-59之间的罗马数字的解决方案，那么这里是一种简单快捷的解决方案。
const getRoman = num => {
if (num===0) {
return "";
}
let result = "";
let n = num%10;
let rest = Math.floor(num/10);
if (n === 0) {
getRoman(rest);
} else if (n<4) {
for (let i=0;i<n; i++) {
result = result + "I";
}
} else if (n === 4) {
result = result + "IV";
} else if (n === 5) {
result = result + "V";
} else if (n < 9) {
result = result + "V";
for (let l = 6; l < 9; l++) {
result = result + "I";
}
} else if (n === 9) {
result = result+"IX";
} else {
result = result + "V";
n = n-5;
for (let i=0; i<n; i++) {
result = result+"I";
}
}
if (rest === 0) {
return result;
} else if (rest<4) {
for (let j = 0; j < rest; j++) {
result = "X" + result;
}
} else if (rest === 4) {
result = "XL" + result;
} else {
result = "L" + result;
}
return result;
}
console.log(getRoman(1))
console.log(getRoman(50))
console.log(getRoman(59))
console.log(getRoman(0))
console.log(getRoman(42))
console.log(getRoman(23))
console.log(getRoman(29))
console.log(getRoman(34))
I
L
LIX
XLII
XXIII
XXIX
XXXIV
答案 5 :(得分：0)
这将处理带有等同罗马字母的较大小数（最多1.000.000）。
/// <summary>
/// Convert decimals to roman numerals
/// </summary>
public static class RomanNumerals
{
/// <summary>
/// Dictionary of roman numbers and their equavilant decimals.
/// IMPORTANT: Keep the order from larger to smaller
/// </summary>
public static Dictionary<uint, string> RomanNumbers =
new Dictionary<uint, string>
{
{ 1000000, "M̅" },
{ 900000, "C̅M̅" },
{ 500000, "D̅" },
{ 400000, "C̅D̅" },
{ 100000, "C̅" },
{ 90000, "X̅C̅" },
{ 50000, "L̅" },
{ 40000, "X̅L̅" },
{ 10000, "X̅" },
{ 9000, "I̅X̅" },
{ 5000, "V̅" },
{ 4000, "I̅V̅" },
{ 1000, "M" },
{ 900, "DM" },
{ 500, "D" },
{ 400, "CD" },
{ 100, "C" },
{ 90, "XC" },
{ 50, "L" },
{ 40, "XL" },
{ 10, "X" },
{ 9, "IX" },
{ 5, "V" },
{ 4, "IV" },
{ 1, "I" },
};
/// <summary>
/// Convert decimal number to roman number
/// </summary>
/// <param name="number">unsigned number</param>
/// <returns>Roman number</returns>
public static string ToRoman(this uint number)
{
var romanNum = string.Empty;
while (number > 0)
{
// Make sure to order from larger to smaller
var item = RomanNumbers
.OrderByDescending(x => x.Key)
.First(x => x.Key <= number);
romanNum += item.Value;
number -= item.Key;
}
return romanNum;
}
}
用法：
uint number = 1000001;
number.ToRoman(); // M̅I
number = 999999;
number.ToRoman(); // C̅M̅X̅C̅I̅X̅DMXCIX
number = 500009;
number.ToRoman(); // D̅IX
请参阅：