Question

我需要MySQL查询的帮助。我有2个表，clients和payments。表格clients有2个字段id和name。表格payments包含id，id_clients，pay_month。客户需要每月支付一定金额。我想只搜索尚未支付当月的客户名称。

我的查询

SELECT name FROM clients WHERE id NOT IN (SELECT DISTINCT id_client FROM payments WHERE pay_month > '2014-03-15' ORDER BY pay_month DESC)

我设法解决了我的疑问。我用php来存储日期$today = date("Y-m-d");

SELECT DISTINCT clients.id, clients.name FROM clients WHERE clients.id NOT IN (SELECT DISTINCT id_clients FROM payments WHERE pay_month > '".$today."' ORDER BY pay_month DESC) ORDER BY clients.name ASC

谢谢大家的帮助。

Answer 1

也许是这样的。

SELECT
    c.name as client_name,
    p.pay_month as payment_month
FROM clients c
LEFT JOIN payments p on p.id_clients = c.id
WHERE p.id IS NULL AND YEAR(p.pay_month) >= YEAR(NOW()) AND MONTH(p.pay_month) > MONTH(NOW());

如果你能给我们一些样本数据，我可以建立一个sql小提琴，并且更容易做到。刚编辑修复日期格式/检查

MySQL查询根据日期排除条目

1 个答案: