Question

我一直在寻找这个。我得到了解决方案。在这里。它是在php中使用AJAX完成的。我有2页是googleapi.php和googleapi.php发送的AJAX请求使用的其他getData.php。

googleapi.php

 <html>
  <head>
    <!--Load the Ajax API-->
    <script type="text/javascript" src="https://www.google.com/jsapi"></script>
    <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js"></script>
    <script type="text/javascript">

    // Load the Visualization API and the piechart package.
    google.load('visualization', '1', {'packages':['corechart']});

    // Set a callback to run when the Google Visualization API is loaded.
    //google.setOnLoadCallback(drawChart);

    function drawChart(object) {

      // Create our data table out of JSON data loaded from server.
      var data = new google.visualization.DataTable(object);
      var options = {
           title: 'Test API',
          is3D: 'true',
          width: 200,
          height: 100
        };
      // Instantiate and draw our chart, passing in some options.
      // Do not forget to check your div ID
      var chart = new google.visualization.ColumnChart(document.getElementById('chart_div'));
      chart.draw(data, options);
    }

    function show()
    {

        xmlhttp = new XMLHttpRequest();
        xmlhttp.open("GET","getdata.php?name=jaspreet",true);
        xmlhttp.send();
        xmlhttp.onreadystatechange = getResponse;
    }
    function getResponse()
    {
        if(xmlhttp.readyState==4){
            alert(xmlhttp.responseText);
            var obj = JSON.parse(xmlhttp.responseText);
            drawChart(obj);
        }
    }
    </script>
  </head>

  <body>
    <!--this is the div that will hold the pie chart-->
    <div id="chart_div"></div>
    <select id="name" onchange="show();">
        <option value="test">test</option>
        <option value="test1">test1</option>
        <option value="test2">test2</option>
    </select>
  </body>
</html>

访问getdata.php

<?php $con=mysql_connect("localhost","root","") or die("Failed to connect with database!!!!");
mysql_select_db("student", $con); 
// The Chart table contains two fields: weekly_task and percentage
// This example will display a pie chart. If you need other charts such as a Bar chart, you will need to modify the code a little to make it work with bar chart and other charts
$sth = mysql_query("SELECT * FROM marks where name='jas'");

/*
---------------------------
example data: Table (Chart)
--------------------------
marks     percentage
English           30
Maths             40
Science            44
*/

$rows = array();
//flag is not needed
$flag = true;
$table = array();
$table['cols'] = array(

    // Labels for your chart, these represent the column titles
    // Note that one column is in "string" format and another one is in "number" format as pie chart only required "numbers" for calculating percentage and string will be used for column title
    array('label' => 'subject', 'type' => 'string'),
    array('label' => 'marks', 'type' => 'number')

);

$rows = array();
while($r = mysql_fetch_assoc($sth)) {
    $temp = array();
    // the following line will be used to slice the Pie chart
    $temp[] = array('v' => (string) $r['subject']); 

    // Values of each slice
    $temp[] = array('v' => (int) $r['marks']); 
    $rows[] = array('c' => $temp);
}

$table['rows'] = $rows;
$jsonTable = json_encode($table);
echo $jsonTable;
?>

就是这样，您需要创建一个数据库。它就像一个魅力。

Answer 1

我知道你的帖子是＆＃34;答案＆＃34;但我想我会插话。如果你想动态地将数据输入谷歌图表，你可以简单地用PHP回声到javascript。 php可用于从您的服务器或mysql表中获取信息。

以下是一个例子：

    <?php   $i = 0; $grab = mysql_query("SELECT * FROM `productList` WHERE 1");
    $pricelist = mysql_fetch_array($grab);
    $numberofproducts = mysql_num_rows($grab);

                              ?>       
    <script type="text/javascript" src="https://www.google.com/jsapi"></script>
    <script type="text/javascript">
    google.load("visualization", "1", {packages:["corechart"]});
    google.setOnLoadCallback(drawChart);
    function drawChart() {
    var data = google.visualization.arrayToDataTable([
      ['parts', 'Prices'],
      ['Number of Products',  <?php echo $numberofproducts;?>],

    ]);

    var options = {
      title: 'Number of Products',
      hAxis: {title: '', titleTextStyle: {color: 'red'}},
                width: 980,
                height: 200
    };

    var chart = new google.visualization.ColumnChart(document.getElementById('chart_div'));
    chart.draw(data, options);
  }

在php mysql中使用Google Chart API显示条形图

1 个答案: