我有一系列文字,例如[building2, building1 , building3, building5, building4]
。
如何按最后一个数字字符对此数组进行排序,因此已排序的数组将为building1, building2, building3, building4, building5, building6
?
答案 0 :(得分:3)
var array = ["building200", "building10", "building3", "building5", "building4"];
array.sort(function(a, b){
var char1 = a.substr(a.search(/\d+$/)); // get the last numbers
var char2 = b.substr(b.search(/\d+$/)); // get the last numbers
return parseInt(char1) - parseInt(char2); // sort by parsing to number
});
alert(array); // ["building3", "building4", "building5", "building10", "building200"]
a.search(/\d/)
将返回遇到的第一个数字的索引,a.substr(that_index)
将从那里剪切字符串直到结束。
如果数组包含长度不均匀的字符串,例如["buildingsss2", "buildisng1", "building3", "building5", "builsding4"]
希望有所帮助!
答案 1 :(得分:3)
您可以使用正则表达式\d+
来获取所有连续数字,然后通过从另一个中减去一个来比较这两个元素,例如
var data = [ 'building2', 'building10', 'building3', 'building5', 'building4' ];
data.sort(function(first, second) {
return /\d+/.exec(first)[0] - /\d+/.exec(second)[0];
});
console.log(data);
<强>输出强>
[ 'building2', 'building3', 'building4', 'building5', 'building10' ]
注意:这比现在发布的其他解决方案更好,因为即使数字大于9,这也可以正常工作。
答案 2 :(得分:2)
使用.sort()方法
var a = ['building2', 'building1' , 'building3', 'building5', 'building4'];
console.log(a.sort());
输出
["building1", "building2", "building3", "building4", "building5"]
不需要自定义功能
答案 3 :(得分:2)
Array.sort
,使用:
['building2', 'building1', 'building3', 'building5', 'building4'].
sort(function(a,b){
return +( /\d{1,}$/.exec(a) || [0] )[0] -
+( /\d{1,}$/.exec(a) || [0] )[0];
}
);
通过这种方式,您还可以对多于10个建筑物进行分类,如中
['building1', 'building12', 'building302', 'building205', 'building400']
并包括不以数字值结尾的字符串