Question

我有以下代码：

<?php

class test{


//here we get the total price for the amount, and print-it on screen
public function priceProd($amount){
    if (!empty($amount)) {
        $price = 5;
        }

    //getting the sum and outputed using echo
    $sum = $price * $amount;
    echo $sum.'<br>';


    //building the array
    $answer = array();
    $answer['sum'] = $sum;

}


//here we get the total price for all the values outputed by the priceProd function
public function sumProd(){ 



}


 //closing the class
 }


 $test = new test;

 //feeding amount values to function and getting multiple sums 
 echo $test->priceProd(2);
 echo $test->priceProd(4);

 //getting all the total of sums
 echo $test->sumProd();


 ?>

如何使函数sumProd成为函数priceProd的所有输出的总和。现在，即使函数的示例未完成，它似乎只接受并输出$ sum的最后一个值。如果我使用数据库来存储所有值，我认为更简单，但是使用这样的原始输出，我不知道如何找到答案。

欢迎任何类型的答案。非常感谢你！

Answer 1

你应该使用array作为函数的返回值..

等。

$answer = array();
$answer['sum'] = $sum;
$answer['price'] = $price;
$answer['product'] = $product;

return $answer;

Answer 2

让我澄清一些事情：

1）。你不能在一个函数中返回两次。（见下面的产品功能）

A）。打印按金额*价格计算的小计的一项功能 - B）。打印总费用的另一个功能。

这将有效：

班级考试{

private $total = array(); 

public function product($product, $amount){
    echo $amount.' - '.$product.' - ';

  $this->amount = $amount;
  $this->product = $product;
 return; // if you need this to return a value, put it here. 
}



public function priceProd($product){
$amount = $this->amount;

if ($product == 'pen') {
    $price = 10;
} elseif ($product == 'gum') {
    $price = 5;
}

$sum = $price * $amount;
$this->total = $this->total + $sum; 
return $this->price = $sum.'<br>';

}



public function sumProd(){ 

    return $this->total; 
// or, from the looks of the rest, you probably want to: 
       echo "Total: ".$this->total;


    }
}

php函数的多个输出的总和

2 个答案: