Question

我将这些数据存储在一个文件中：

00 00 1a 00 2f 48 00 00  88 9f 5d 04 00 00 00 00   
10 04 a8 09 a0 00 c8 00  00 00 80 00 00 00 ff ff   
ff ff ff ff 00 25 9c 8f  d5 bf 00 25 9c 8f d5 bf   
40 7f 04 30 bc 61 02 00  00 00 64 00 21 04 00 05   
54 49 52 41 44 01 04 82  84 8b 96 03 01 0d 05 04   
00 01 00 00 20 01 00 2a  01 00 32 08 0c 12 18 24   
30 48 60 6c dd 18 00 50  f2 02 01 01 03 00 03 a4   
00 00 27 a4 00 00 42 43  5e 00 62 32 2f 00 dd 05   
00 50 f2 05 00 dd 0e 00  50 f2 04 10 4a 00 01 10   
10 44 00 01 02 dd 05 00  09 86 01 00 fe 66 cf c2

我希望使用python来定义一个包含16列和10行的矩阵，其中包含文件中的数据。

请注意，例如ff或40代表1个字节。

Answer 1

这样的事情？

data = ''
with open ("in.txt", "r") as in_file:
    data = in_file.read().split(' ')
with open ("out.txt", "w") as out_file:
    position = 0
    for i in data:
        if 0 == (position % 16):
            out_file.write ("\r\n") #next line windows style.  for unix it should be \n
        out_file.write ("%s " % i)
        position += 1

使用python定义字节数据矩阵

1 个答案: