我必须实现T9词典。
基本上，当我按下9个键中的任何一个时，它应该显示给我 可以使用该组合键开始的前5个单词。
如果我输入＆＃39; 46＆＃39;它可以提供＆＃39; hotel＆＃39;或者“好”＆＃39;取决于我是否 意图＆＃39; g＆＃39;或者＆＃39; h＆＃39;当我按下4时。
优先级取决于哪些单词相对受欢迎 - 您可以 例如，使用前100 000个单词中的前5000个单词。
我正在做的代码是：
导入
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.util.Date;
import java.util.HashMap;
import java.util.LinkedList;
import java.util.List;
import java.util.Map;
T9Dict课程
public class T9Dict {
private static final Runtime s_runtime = Runtime.getRuntime();
public static void main(String[] args) throws Exception {
runGC();
long heap1 = usedMemory();
long start = new Date().getTime();
Trie trie = Trie.getInstance();
System.out.println("Creating Dictionary");
File f = new File("C:\\Users\\hp1\\Desktop\\100kfound.txt");
BufferedReader br = new BufferedReader(new FileReader(f));
String s = br.readLine();
int i = 0;
do {
i++;
trie.add(s);
s = br.readLine();
} while (s != null);
br.close();
long end = new Date().getTime();
long time = (end - start);
System.out.println("Loaded Dictionary with " + i + " words in " + time
+ " msec");
// runGC();
long heap2 = usedMemory(); // take an "after" heap snapshot:
System.out.println("Memory used = " + (heap2 - heap1));
String pattern = "4663";
start = new Date().getTime();
String word = trie.getWord(pattern);
end = new Date().getTime();
time = (end - start);
System.out.println("Found word : " + word + " in " + time + " msec");
}
private static void runGC() throws Exception {
// for whatever reason it helps to call Runtime.gc()
// using several method calls:
for (int r = 0; r < 4; ++r) {
_runGC();
}
}
private static void _runGC() throws Exception {
long usedMem1 = usedMemory();
long usedMem2 = Long.MAX_VALUE;
for (int i = 0; (usedMem1 < usedMem2) && (i < 1000); ++i) {
s_runtime.runFinalization();
s_runtime.gc();
Thread.currentThread().yield();
usedMem2 = usedMem1;
usedMem1 = usedMemory();
}
}
private static long usedMemory() {
return s_runtime.totalMemory() - s_runtime.freeMemory();
}
}
Trie class
class Trie {
private static final String regex = "[a-zA-Z]*";
private static Trie instance = null;
Node root = null;
Map<Character, Integer> map = new HashMap<Character, Integer>();
private Trie() {
map.put('a', 2);
map.put('b', 2);
map.put('c', 2);
map.put('d', 3);
map.put('e', 3);
map.put('f', 3);
map.put('g', 4);
map.put('h', 4);
map.put('i', 4);
map.put('j', 5);
map.put('k', 5);
map.put('l', 5);
map.put('m', 6);
map.put('n', 6);
map.put('o', 6);
map.put('p', 7);
map.put('q', 7);
map.put('r', 7);
map.put('s', 7);
map.put('t', 8);
map.put('u', 8);
map.put('v', 8);
map.put('w', 9);
map.put('x', 9);
map.put('y', 9);
map.put('z', 9);
}
private int getVal(char c) {
return map.get(c);
}
public static Trie getInstance() {
if (instance == null) {
synchronized (Trie.class) {
instance = new Trie();
}
}
return instance;
}
public String getWord(String pattern) {
String s = null;
Node node = root;
int i = 0;
int num = 0;
while (i < pattern.length()) {
num = pattern.charAt(i) - '0';
if (num == node.val) {
i++;
if (i == pattern.length()) {
s = node.list.get(0);
}
node = node.middle;
} else if (num < node.val) {
if (i == pattern.length()) {
s = node.list.get(0);
}
node = node.left;
} else {
if (i == pattern.length()) {
s = node.list.get(0);
}
node = node.right;
}
}
return s;
}
public void add(String s) {
if (s.length() > 0) {
s = s.toLowerCase();
System.out.println("Adding : " + s);
if (root == null) {
root = new Node(this.getVal(s.charAt(0)));
Node node = root;
Node temp = null;
for (int i = 1; i < s.length(); i++) {
temp = new Node(getVal(s.charAt(i)));
node.middle = temp;
node = temp;
if (i == s.length() - 1) {
temp.set(s);
}
}
} else {
Node node = root;
int i = 0;
Node temp = null;
int val = 0;
while (i < s.length()) {
val = getVal(s.charAt(i));
if (node.val == val) {
if (i == s.length() - 1) {
node.set(s);
i++;
} else {
i++;
if (node.middle == null) {
while (i < s.length()) {
val = getVal(s.charAt(i));
temp = new Node(val);
node.middle = temp;
node = temp;
if (i == s.length() - 1) {
temp.set(s);
}
i++;
}
} else {
node = node.middle;
}
}
} else if (val < node.val) {
if (node.left == null) {
temp = new Node(val);
node.left = temp;
node = temp;
if (i == s.length() - 1) {
temp.set(s);
} else {
i++;
while (i < s.length()) {
val = getVal(s.charAt(i));
temp = new Node(val);
node.middle = temp;
node = temp;
if (i == s.length() - 1) {
temp.set(s);
}
i++;
}
}
} else {
node = node.left;
}
} else {
if (node.right == null) {
temp = new Node(val);
node.right = temp;
node = temp;
if (i == s.length() - 1) {
temp.set(s);
} else {
i++;
while (i < s.length()) {
val = getVal(s.charAt(i));
temp = new Node(val);
node.middle = temp;
node = temp;
if (i == s.length() - 1) {
temp.set(s);
}
i++;
}
}
} else {
node = node.right;
}
}
}
}
}
}
}
节点类
class Node {
int val;
Node left;
Node middle;
Node right;
List<String> list = new LinkedList<String>();
public Node(int val) {
this.val = val;
}
public void set(String s) {
list.add(s);
}
public String toString() {
return String.valueOf(val);
}
}
此代码在添加到Trie时提供nullpointerexception 我找不到解决方案请帮忙
答案 0 :(得分：0)
当我运行此命令时，我发现此行发生异常：
root = new Node(this.getVal(s.charAt(0)));
让我们展开这个，你将“单词”的第一个字符（即字符串，s）传递给getVal()，这反过来将返回一个int if和only only如果，该字符是小写字母，az。
当我运行文件时，“word”是6724 yahoo - 这是你链接到的字典文本文件的第一行。您的代码中没有任何内容可以清除此行以获取实际的单词本身，而是面向一系列空格，然后是数字。
因此失败的原因是因为你有效地前往this.getVal(" ")。如果您致电map.get()且密钥不存在，则会返回null（如Map documentation中所述）。
获取单词本身而不是空白或频率数字的一种简单方法是首先处理字符串：
s = s.trim(); // removes all leading and trailing whitespace
String word = s.substring(s.indexOf(" ")+1); // extract just the word after the space
然后你可以传递word的第一个字符：
root = new Node(this.getVal(word.charAt(0)));
答案 1 :(得分：0)
1 - 您的文件不包含字符。它是二进制文件，因此您应该使用FileInputStream对象来读取它。
2 - 在读取文件并在Trie中添加字符串时，您应该验证此字符串不为空，否则它会抛出NullPointerException。您可以像这样运行文件：