Question

在以下DataFrame中，我需要在＆＃39; a＆＃39;中搜索所有字符串。

df = pd.DataFrame({'id' : [1,2,3,4],
                'path'  : ["p1,p2,p3,p4","p1,p2,p1","p1,p5,p5,p7","p1,p2,p3,p3"]})

需要检查是否＆＃39; p1＆＃39;和＆＃39; p2＆＃39;可用。

a = ['p1','p2']

如下所示

if all(x in df.path for x in a):
    print df

Answer 1

这个怎么样？

import pandas as pd

df = pd.DataFrame({'id': [1,2,3,4],
       'path': ["p1,p2,p3,p4","p1,p2,p1","p1,p5,p5,p7","p1,p2,p3,p3"]})

a = [ 'p1', 'p2']

# see: http://stackoverflow.com/a/470602/1407427
reg_exp = ''.join(['(?=.*%s)' % (i) for i in a])

# alternatively: print df.path.str.match(reg_exp, as_indexer=True)
print df.path.str.contains(reg_exp)

结果：

0     True
1     True
2    False
3     True
Name: path, dtype: bool

Pandas DataFrame搜索列中可用列表中的所有字符串

1 个答案: