Question

n下面的xml，

<?xml version="1.0" encoding="utf-8"?>
<Models>
    <Model  DESC="HONDA-BLUE-450"  MODELID="XX12-01"  Status="in" />
    <Model  DESC="VOLKS--RED-345"  MODELID="XY12-01"  Status="in" />
    <Model  DESC="BENZ-BLUE-550"  MODELID="XX12-01"  Status="in" />
    <Model  DESC="VOLKS--CYAN-345"  MODELID="BG12-01"  Status="out" />
    <Model  DESC="HONDA-GREEN-234"  MODELID="AX12-01"  Status="in" />
    <Model  DESC="VOLKS-Yellow-765"  MODELID="XY11-01"  Status="in" />
    <Model  DESC="HONDA-GREEN-109"  MODELID="AC12-01"  Status="in" />
    <Model  DESC="AUDI-GREEN-984"  MODELID="AF42-01"  Status="in" />
    <Model  DESC="VOLKS-Yellow-565"  MODELID="XJ11-61"  Status="out" />
    <Model  DESC="HONDA-WHITE-079"  MODELID="DC12-38"  Status="in" />
    <Model  DESC="TOYOTA-GREY-109"  MODELID="UC12-81"  Status="in" />
    <Model  DESC="AUDI-CYAN-984"  MODELID="LF42-41"  Status="in" />
    <Model  DESC="VOLKS-WHITE-865"  MODELID="LK11-61"  Status="out" />
    <Model  DESC="HONDA-GREY-039"  MODELID="PC12-31"  Status="in" />
</Models>

我想得到状态为out的所有MODELID值，DESC以VOLKS开头。任何帮助将不胜感激。

Answer 1

您可以使用linq to xml遍历xml节点和String.StartsWith以检查atttribute DESC值是否以“VOLKS”开头：

XDocument xdoc = XDocument.Load("data.xml");
var modelIds= from c in xdoc.Descendants("Model")
              where c.Attribute("DESC").Value.StartsWith("VOLKS")  &&
               c.Attribute("Status").Value == "out"
              select c.Attribute("MODELID").Value;

或使用正则表达式SQL LIKE：

XDocument xdoc = XDocument.Load("data.xml"));
var modelIds= from c in xdoc.Descendants("Model")
              where c.Attribute("DESC").Value.Like("VOLKS%")  &&
               c.Attribute("Status").Value == "out"
              select c.Attribute("MODELID").Value;

为LIKE使用正则表达式：

public static class MyStringExtensions
{
public static bool Like(this string toSearch, string toFind)
{
    return new Regex(@"\A" + new Regex(@"\.|\$|\^|\{|\[|\(|\||\)|\*|\+|\?|\\").Replace(toFind, ch = > @"\" + ch).Replace('_', '.').Replace(" % ", ".*") + @"\
            z ", RegexOptions.Singleline).IsMatch(toSearch);
 }
}

LIKE source

Answer 2

您没有提及LINQ是否正常。这是一个使用LINQ，foreach和XPATH的方法。（为了加强Mihai已经发布的报道）。

    static void Main(string[] args)
    {
        XmlDocument xd = new XmlDocument();
        xd.Load("Models.xml");
        var result = from XmlNode row in xd.DocumentElement.SelectNodes("//Model[starts-with(@DESC, 'VOLKS') and @Status='out']") where row != null select row;
        foreach (var x in result)
        {
            XmlAttributeCollection attributes = x.Attributes;
            Console.Write("<Model ");
            foreach (XmlAttribute attribute in x.Attributes)
            {
                Console.Write("{0}=\"{1}\"  ", attribute.Name, attribute.Value);
            }
            Console.WriteLine(" />");
        }
    }

Answer 3

使用lambdas的Linq to XML解决方案：

var query = XDocument.Load("data.xml").Root.Elements("Model")
   .Where(m => m.Attribute("Status").Value == "out" && m.Attribute("DESC").Value.StartsWith("VOLKS")) 
   .Select(m => m.Attribute("MODELID").Value);

foreach (var v in query)
    Console.WriteLine(v);

//  output:
//    BG12-01
//    XJ11-61
//    LK11-61

使用XmlDocument获取字符串或变量中特定类型的innertag值

3 个答案: