我想自己生成验证码而不使用任何其他API,但这里有一些问题。在我的代码中,我将每个角色视为一个图像,然后在它们上形成一些操作,但现在我想根据其中点旋转整个图像。
以下是我的示例代码:
for (int i = 0; i < charsToPrint; i++)
{
double randomValue =Math.random();
int randomIndex = (int) Math.round(randomValue * (chars.length - 1));
char characterToShow = chars[randomIndex];
finalString.append(characterToShow);
int charWidth = fontMetrics.charWidth(characterToShow);
int charDim = Math.max(maxAdvance, fontHeight);
//int halfCharDim = (int) (charDim / 2);
charImage = new BufferedImage(charDim, charDim,BufferedImage.TYPE_INT_ARGB);
charGraphics = charImage.createGraphics();
charGraphics.setColor(textColor);
charGraphics.setFont(textFont);
int rn = ran.nextInt((20 - 10) + 1) + 10;
x1=charDim/rn;
int rn1 = ran.nextInt((20 - 10) + 1) + 10;
y1=charDim/rn1;
int charX = (int) ((0.5 * charDim - 0.5 * charWidth)+x1);
int charY=(int) ((charDim - fontMetrics.getAscent()) / 2 + fontMetrics.getAscent()+y1);
charGraphics.drawString("" + characterToShow, charX, charY);
float x = horizMargin + spacePerChar * (i) - charDim / 2.0f;
int y = (int) ((height - charDim) / 2);
g.setColor(Color.GREEN);
g.drawImage(charImage, (int) (x+x1), (int)(y+y1), charDim,charDim, null,null);
charGraphics.dispose();
}