Question

我正在尝试从联系人那里获取电话号码的值，但我要么[对象，对象]返回给我或者根本没有。当我尝试匹配[i] .phoneNumbers时，我得到[object，Object]，当我添加匹配[i] .phoneNumbers [0] .value时，我的警报完全停止。

function callme() {
    var options = new ContactFindOptions();
    options.filter = ""; //leaving this empty will find return all contacts
    options.multiple = true; //return multiple results
    console.log(options);
    var filter = ["displayName", "phoneNumbers"]; //an array of fields to compare against the options.filter 

    navigator.contacts.find(filter, successFunc, errFunc, options);

    function successFunc(matches) {
        for (var i = 0; i < matches.length; i++) {
            //this loops through all of the contacts

            var contact_name = matches[i].displayName;
            var contact_number = matches[i].phoneNumbers; //this returns [object, Object]
            // var contact_number = matches[i].phoneNumbers[0].value; returns nothing at all
            var contact_full = contact_name + " " + contact_number;
        }
        alert(contact_full);
    }

    function errFunc() {
        alert("oh no!");
    }
};

Answer 1

我不确定您的JSON对象的结构是什么，但您可以在firebug中进行调试，如果您不确定如何执行此操作，请尝试以下操作：

function successFunc(matches) {
        for (var i = 0; i < matches.length; i++) {
            //this loops through all of the contacts

        var contact_name = matches[i].displayName;
        alert(JSON.stringify(matches[i].phoneNumbers);
var contact_number = matches[i].phoneNumbers; //this returns [object, Object]
            // var contact_number = matches[i].phoneNumbers[0].value; returns nothing at all
            var contact_full = contact_name + " " + contact_number;

    }
    alert(contact_full);
}

警报对话框出现后，您将能够看到对象的属性列表。

.value什么都没有（javaScript）

1 个答案: