Question

我是bash的新手，我正在尝试编写一个基本脚本来解析文件并将某些awk的元素存储在一个数组中，以并列方式并排打印。我已经定义了数组并且命令正常工作，但是我想使用getops来定义输出。抱歉，如果我不清楚，但希望psedocode会解释。

为任何帮助干杯，斯科特

#!/bin/bash

# Defined arrays
INPUTFILE=$2
ARRAYA=$(Code to process a file and extract column A)
ARRAYB=$(Code to process a file and extract column B)
ARRAYC=$(Code to process a file and extract column C)
ARRAYD=$(Code to process a file and extract column D)

# Define getops arguments
while getopts "A:B:C:D:" arg; do
     case $arg in
         A)
       "I want to use $ARRAYA"
       shift
       ;;
         B)
       "I want to use $ARRAYB"
       shift
       ;;
         C)
       "I want to use $ARRAYC"
       shift
           ;;
         D)
       "I want to use $ARRAYD"
       shift
           ;;
    esac
done

# Sample command construction for "myscript.sh -ABCD $INPUTFILE"
for ((i=0; i<=${#ARRAYA[@]}; i++)); do
    echo "${ARRAYA[i]}" "${ARRAYB[i]}" "${ARRAYC[i]}" "${ARRAYD[i]}"
done

# Sample command construction for "myscript.sh -DCB $INPUTFILE"
for ((i=0; i<=${#ARRAYD[@]}; i++)); do
    echo "${ARRAYD[i]}" "${ARRAYC[i]}" "${ARRAYB[i]}"
done

Answer 1

这里的丑陋：使用bash间接变量

#!/bin/bash

ARRAYA=( a1 a2 a3 a4 a5 )
ARRAYB=( b1 b2 b3 b4 b5 )
ARRAYC=( c1 c2 c3 c4 c5 )
ARRAYD=( d1 d2 d3 d4 d5 )

order=()
while getopts ":ABCD" arg; do
     case $arg in
         A) order+=("ARRAYA") ;;
         B) order+=("ARRAYB") ;;
         C) order+=("ARRAYC") ;;
         D) order+=("ARRAYD") ;;
    esac
done
shift $((OPTIND - 1))

(( ${#order[@]} == 0 )) && exit

for ((i=0; i<=${#ARRAYA[@]}; i++)); do
    for ary in "${order[@]}"; do
        elem="${ary}[$i]"
        echo -n "${!elem} "
    done
    echo
done

测试：

$ bash abcd.sh -A
a1 
a2 
a3 
a4 
a5 

$ bash abcd.sh -BA
b1 a1 
b2 a2 
b3 a3 
b4 a4 
b5 a5 

$ bash abcd.sh -BAC
b1 a1 c1 
b2 a2 c2 
b3 a3 c3 
b4 a4 c4 
b5 a5 c5 

$ bash abcd.sh -DCBA
d1 c1 b1 a1 
d2 c2 b2 a2 
d3 c3 b3 a3 
d4 c4 b4 a4 
d5 c5 b5 a5 

$ bash abcd.sh 
(no output)

我可以使用getops为命令定义动态构造吗？

1 个答案: