这是我所遇到的一个问题,并且我还在继续。 我在这里发了一个问题:Updating an array on button click Javascript已经但我仍然无法找到解决方案。也许我没有完全清楚地解释它。
基本上,我的目标是在用户点击链接时从数组中删除元素。我的程序当前所执行的操作是将其从数组中删除(我可以通过我用来测试的警报来判断)和屏幕。但是,当我再次从头开始添加元素时 似乎重新添加/保留刚刚删除的值。
var theImages = new Array();
//When the user clicks save
//The image(dataURI) is added to an array.
//JSON.stringify function used to store the dataURIs in localStorage:
function save(URL) {
theImages.push(URL);
var x = JSON.stringify(theImages);
localStorage.setItem('images', x);
//drawImages function called and the array is passed through in string form.
drawImages(x);
}
function drawImages(array){
//Convert the array back into array form:
array = JSON.parse(array);
//array = [];
//If an image is saved, display the saveArea div:
if (array.length > 0){
document.getElementById("saveArea").style.visibility="visible";
}
//Clear the elements that might already be in the div so they don't appear twice:
var theDiv = document.getElementById("saveArea");
while (theDiv.firstChild) {
theDiv.removeChild(theDiv.firstChild);
}
//Loop to display all images in the array:
for (var x=0; x < array.length; x++){
//alert(array.length);
//Create image for each value in array:
//Create a div to contain each image:
var divimg = document.createElement("div");
divimg.style.marginRight="10px";
//divimg.style.border = "1px dotted red";
divimg.className = "saveContainer";
divimg.style.width = 300+"px";
divimg.style.padding = 5+"px";
divimg.style.marginRight="10px";
divimg.style.height = 150+"px";
divimg.style.display="inline-block";
divimg.style.marginRight="35px";
//Add the container(s) to the surrounding main container:
document.getElementById("saveArea").appendChild(divimg);
//Create the image:
var img = document.createElement("img");
//Set the source equal to point x in the
//Array of dataURIs
img.src = array[x];
img.width = 300;
img.height = 150;
img.setAttribute("id", "theImageId");
img.style.marginRight="10px";
img.className = "saveImg";
//Add each image to the containing div:
divimg.appendChild(img);
//Create close button:
var close = document.createElement("img");
close.src="close.png";
close.width = 50;
close.height = 50;
close.border = 0;
close.style.position="relative";
close.style.bottom=115+"px";
close.style.right=40+"px";
close.className="closeButton";
//close.style.cssFloat="right";
//close.style.right= 0+"px";
var link = document.createElement("a");
link.href = "#";
//Make the close button image a link:
link.appendChild(close);
link.nameIndex = x;
//When the close button is clicked:
link.onclick = (function (x) {
var imageNum = this.nameIndex;
alert("You clicked to close image "+(imageNum+1));
//Remove the image:
array.splice(x,1);
alert("The length of this array is: "+array.length);
//Update localStorage:
localStorage.removeItem('images');
//Put array back in string form to store in local storage
array = JSON.stringify(array);
localStorage.setItem('images', array);
//Call the function again and pass it the updated array:
drawImages(array);
} );
//Add the close button the the containing div:
divimg.appendChild(link);
//divimg.appendChild(close);
} //End Loop
} //End drawImages();
我真的无法让这个工作。我找不到问题&amp;我希望/感谢任何帮助,因为在这个阶段我真的很讨厌。 &GT;(
我确实已经意识到这已经发布了,但觉得有必要进一步解释和评论。
如果不清楚问题是什么,我将回答您对该代码的任何问题。
答案 0 :(得分:1)
您的问题是您没有使用单个阵列。单击“保存”会将元素添加到全局的aImages数组中,但不会将图像传递给drawImages。单击a.close将删除&#39;数组中的元素。数组,但它不会改变图像。因此,当您单击“保存”时,会添加“图像”,但永远不会从中删除。你可能应该寻求一个解决方案,你不要将你的数组转换为字符串,然后再转回,但为了让你的代码工作量最少,我认为只需分配数组&#39;到图像会做到这一点:
function drawImages(array){
//Convert the array back into array form:
array = JSON.parse(array);
theImages = array;
/* ... */
}
答案 1 :(得分:0)
尝试更改将信息再次保存到本地存储的方式。
此行下的代码:
alert("You clicked to close image "+(imageNum+1));
测试一下:
var imgArr = JSON.parse(localStorage.getItem('images'));
imgArr.splice(x, 1);
alert("The length of this array is: "+imgArr.length);
localStorage.removeItem('images');
localStorage.setItem('images', JSON.stringify(imgArr));
drawImages(imgArr);
请告诉我。
我假设通过使用array
作为变量,它始终访问包含完整图像列表的现有变量。因此,splice()
可能会删除当前正在删除的图片,但是&#34;恢复&#34;以前删除过的任何其他内容。
如果您将x
传递给函数(图像索引),那么执行var imageNum = this.nameIndex;
会有什么用处。不妨使用x
:alert("You clicked to close image "+(x+1));
。