Question

我已使用array_merge()合并了两个具有相同信息但使用不同键的多维数组，并获得输出：

   Array
   (
    [0] => Array
    (
        [Ttitle] => lilly
        [Price] => 1.75
        [Number] => 3
    )
    [1] => Array
    (
        [Title] => rose
        [Price] => 1.25
        [Number] => 15
    )
    [2] => Array
    (
        [Title] => daisy
        [Price] => 0.75
        [Number] => 25
    )
    [3] => Array
    (
        [Title] => nettle
        [Price] => 2.75
        [Number] => 33
    )
    [4] => Array
    (
        [Title] => orchid
        [Price] => 1.15
        [Number] => 7
    )
  )

正如您所看到的，数组中的第一个键名是Ttitle，其余的是Title。我现在想要的是将所有Ttitle个密钥（仅限于当前的密钥）更改为Title（与所有其他密钥一样）。当我使用array_map()功能时，我设法将所有密钥更改为Title，但我还删除了除了Title密钥之外的所有Ttitle值，我刚刚更改为{{1} }}

代码如下：

Title

此代码的输出：

   if(! empty($notmatchingarray))
   {
    $completearray = array_merge($notmatchingarray, $datastuff2);

    $completearray = array_map(function($complete) {
        return array(
           'Title' => $complete['Ttitle'],
           'Price' => $complete['Price'],
           'Number' => $complete['Number'],
       );
}, $completearray);

echo "Array which includes each unique enrty from both arrays";
echo "<pre>";
print_r($completearray);
echo "</pre>";
echo "<br/>";
   }

我在使用这个Array ( [0] => Array ( [Title] => lilly [Price] => 1.75 [Number] => 3 ) [1] => Array ( [Title] => [Price] => 1.25 [Number] => 15 ) [2] => Array ( [Title] => [Price] => 0.75 [Number] => 25 ) [3] => Array ( [Title] => [Price] => 2.75 [Number] => 33 ) [4] => Array ( [Title] => [Price] => 1.15 [Number] => 7 ) )函数时做错了吗？我应该做除此之外的其他事情吗？

Answer 1

更好的方式，但我走了出去。使用现有代码，您需要设置Ttitle或Title中的任何一个：

$completearray = array_map(function($complete) {
        $title = isset($complete['Ttitle']) ? $complete['Ttitle'] : $complete['Title'];
        return array(
           'Title' => $title,
           'Price' => $complete['Price'],
           'Number' => $complete['Number'],
       );
}, $completearray);

Ternary operator是简单if / else的快捷方式，因此：

if(isset($complete['Ttitle'])) {
    $title = $complete['Ttitle']; //if Ttitle is set use it
} else {
    $title = $complete['Title'];  //if not use Title
}

Answer 2

您可以尝试使用array_key_exists功能：

$completearray = array_map(function($complete) {
    return array(
       'Title' => (array_key_exists('Title', $complete) 
                   ? $complete['Title'] 
                   : $complete['Ttitle']),
       'Price' => $complete['Price'],
       'Number' => $complete['Number'],
   );
}, $completearray);

或者如果您愿意：

$completearray = array_map(function($complete) {
    $titleKey = array_key_exists('Title', $complete) ? 'Title' : 'Ttitle';
    return array(
       'Title' => $complete[$titleKey],
       'Price' => $complete['Price'],
       'Number' => $complete['Number'],
   );
}, $completearray);

如果数组$complete包含密钥'Title'，它将使用该密钥;否则它将使用密钥'Ttitle'。

使用PHP在多维数组上使用array_map更改键

2 个答案: