# script.py
greeting = "hi"
import inspect; import traceback; print traceback.format_stack(inspect.currentframe())[-1]
print greeting
脚本第四行的代码打印出文件名,行号和当前行:
$ python script.py
File "script.py", line 4, in <module>
import inspect; import traceback; print traceback.format_stack(inspect.currentframe())[-1]
hi
但是,如何打印下一行(print greeting
)的行号和内容而不是当前行?
这对于调试很方便,oneliner可以显示它下面的行代码。
通过Ben的回答我得到了这个可怕的生物:
import inspect; import sys; _lne = inspect.currentframe().f_lineno; print "{0}, line {1}:".format(__file__, _lne+1); print open(sys.argv[0]).readlines()[_lne].strip()
它长达166个字母,非常冗长。请注意,当没有下一行时,它会引发IndexError
。
正在运行python script.py
会打印出以下内容
script.py, line 5:
print greeting
hi
我希望我发布的原始行中的一些细微更改可能会导致所需的行为,因为它包含文件名和数字,而无需显式打印这些。它提供的缩进也不受欢迎。
答案 0 :(得分:1)
import inspect; import sys ; print open(sys.argv[0]).readlines()[inspect.currentframe().f_lineno].strip()
虽然这可能不太有用。
答案 1 :(得分:1)
添加一个小帮助函数来查找并打印相关的文件名和行:
import inspect, linecache
def show_next(cf):
'Show the line following the active line in a stackframe'
filename = cf.f_code.co_filename
line = cf.f_lineno
print linecache.getline(filename, line+1)
greeting = "hi"
show_next(inspect.currentframe())
print greeting
当然,如果需要,它可以进入一行:
greeting = "hi"
import inspect, linecache; _f=inspect.currentframe(); print linecache.getline(_f.f_code.co_filename, _f.f_lineno+1)
print greeting
答案 2 :(得分:1)
代码:
# Put format_stack_offset() in a separate module to invoke as needed
def format_stack_offset(frame=None, offset=1):
from traceback import linecache
import inspect;
if not frame:
frame = inspect.currentframe().f_back
lineno = frame.f_lineno + offset
co = frame.f_code
filename = co.co_filename
name = co.co_name
linecache.checkcache(filename)
line = linecache.getline(filename, lineno, frame.f_globals)
retVal = '\n File "%s", line %d, in %s' % (filename, lineno, name)
if line:
retVal += "\n " + line.strip()
return retVal
# script.py
greeting = "hi"
print format_stack_offset() # This is a one liner to show next line
print greeting
可生产
File "/tmp/script.py", line 22, in <module>
print greeting
hi
答案 3 :(得分:0)
from inspect import currentframe, getframeinfo frameinfo = getframeinfo(currentframe()) print frameinfo.filename, frameinfo.lineno