而不是添加到我的问题here,我正在添加一个新问题,因为一旦我用我的X射线视觉护目镜查看我的代码,我就不会理解它。
我甚至不记得我在哪里获得这段代码,但它是我在某处找到的一个例子的改编版。然而,似乎数据甚至没有被发送到服务器。具体来说,这段代码:
public static string SendXMLFile(string xmlFilepath, string uri)
{
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uri);
request.KeepAlive = false;
request.ProtocolVersion = HttpVersion.Version10;
request.Method = "POST";
StringBuilder sb = new StringBuilder();
using (StreamReader sr = new StreamReader(xmlFilepath))
{
String line;
while ((line = sr.ReadLine()) != null)
{
// test to see if it's finding any lines
//MessageBox.Show(line); <= works fine
sb.AppendLine(line);
}
byte[] postBytes = Encoding.UTF8.GetBytes(sb.ToString());
request.ContentLength = postBytes.Length;
// Did the sb get into the byte array?
//MessageBox.Show(request.ContentLength.ToString()); <= shows "112" (seems right)
request.KeepAlive = false;
request.ContentType = "application/xml";
try
{
Stream requestStream = request.GetRequestStream();
// now test this: MessageBox.Show() below causing exception? See https://stackoverflow.com/questions/22358231/why-is-the-httpwebrequest-body-val-null-after-crossing-the-rubicon
//MessageBox.Show(string.Format("requestStream length is {0}", requestStream.Length.ToString()));
requestStream.Write(postBytes, 0, postBytes.Length);
MessageBox.Show(string.Format("requestStream length is {0}", requestStream.Length.ToString()));
requestStream.Close();
using (var response = (HttpWebResponse)request.GetResponse())
{
return response.ToString();
}
}
catch (Exception ex)
{
MessageBox.Show("SendXMLFile exception " + ex.Message);
request.Abort();
return string.Empty;
}
}
}
......似乎是这样做的:
0) Reads the contents of the file at xmlFilepath and puts it into a StreamReader ("sr")
1) A StringBuilder ("sb") is populated with the contents of the StreamReader
2) The contents of the StringBuilder are put into an array of Bytes ("postBytes")
- then here comes the weird part (or so it seems to me, after analyzing the code more closely):
3) The contents of the array of bytes are written to a Stream ("requestStream")
4) The Stream is closed (???)
5) The HttpWebRequest ("request") attempts to return a HttpWebResponse by calling GetResponse()
这段代码是荒谬的,还是我只是不喜欢它?
答案 0 :(得分:1)
GetRequestStream()
返回一个流,该流通过HttpWebRequest转发到网络
您的代码不必要很长,但是正确。
然而,response.ToString()
是错误的;您想要使用response.GetResponseStream()
阅读StreamReader
。