Question

public class hello extends Activity, ListActivity {
    WebView main_webv;  
    ListView main_listv;
    public static final int REFRESHLIST_ID = Menu.FIRST;

    private Handler mHandler = new Handler();
    private static final String SPLASH = "http://";
    private static final String LIST_NAMES = "http://";

    private class HelloWebViewClient extends WebViewClient {
        @Override
        public boolean shouldOverrideUrlLoading(WebView view, String url) {
            view.loadUrl(url);
            return true;
        }
    }

    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        requestWindowFeature(Window.FEATURE_NO_TITLE);

        setContentView(R.layout.main);
        main_webv = (WebView) findViewById(R.id.mainwebview);
        main_webv.setWebViewClient(new HelloWebViewClient());
        main_webv.getSettings().setJavaScriptEnabled(true);
        main_webv.getSettings().setSupportZoom(false);
        main_webv.addJavascriptInterface(new HelloJavascriptInterface(),"hello");
        main_webv.setWebChromeClient(new HelloWebChromeClient());
        main_webv.loadUrl(SPLASH);  
        main_webv.setVisibility( 4 );

        setContentView(R.layout.main_list);         
        main_listv = (ListView) findViewById(R.id.mainlistview);    

    }

如您所见，我首先创建一个webview。然后，我希望它立即消失。然后，我希望Listview出现。但问题是，如果我不做ListActivity，我不能做Listview ......但是我不能做Activity ...

Answer 1

如果没有ListView，您肯定可以ListActivity。您还可以将WebView与ListActivity一起使用。

Answer 2

您可以查看我在您的其他（可能相关的）主题中发布的代码：here。我要复制相同的代码：这是我的布局XML（weblister.xml）：

<?xml version="1.0" encoding="utf-8"?>
<FrameLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    >
    <ListView
    android:id="@+id/list_view"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    />
    <WebView
    android:id="@+id/webview"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    />

</FrameLayout>

现在，我创建一个Activity，它在View视图中同时包含ListView和WebView，但只有其中一个是可见的：

public class WebAct extends Activity {
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        // TODO Auto-generated method stub
        super.onCreate(savedInstanceState);
        setContentView(R.layout.weblister);

            //setup listview
        ListView listView = (ListView) findViewById(R.id.list_view);
        listView.setAdapter(new ArrayAdapter<String>(this,
                android.R.layout.simple_list_item_1,
                new String[]{"One","Two"}){

        });
            // setup web view
        WebView webView = (WebView) findViewById(R.id.webview);

        webView.getSettings().setJavaScriptEnabled(true);
        webView.getSettings().setSupportZoom(false);

        webView.loadUrl("http://www.google.com");

            // set visibility    
        listView.setVisibility(View.INVISIBLE);
        webView.setVisibility(View.VISIBLE);
    }

}

Answer 3

// main.xml中

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
>
<RelativeLayout android:id="@+id/lister"
             android:layout_width="match_parent"
             android:layout_height="300dp"
             android:layout_alignParentTop="true">
<ListView
android:id="@+id/list_view"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
/>
</RelativeLayout>

<RelativeLayout android:id="@+id/webviewer"
         android:layout_width="match_parent"
         android:layout_height="300dp"
         android:layout_below="@+id/lister">    
<WebView
android:id="@+id/webview"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
/>
</RelativeLayout>

// java file

package list.View;

import android.app.Activity;
import android.os.Bundle;
import android.view.View;
import android.webkit.WebView;
import android.widget.ArrayAdapter;
import android.widget.ListView;


public class ListViewActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
    // TODO Auto-generated method stub
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

        //setup listview
    ListView listView = (ListView) findViewById(R.id.list_view);
    listView.setAdapter(new ArrayAdapter<String>(this,
            android.R.layout.simple_list_item_1,
            new String[]{"One","Two"}){

    });
        // setup web view
    WebView webView = (WebView) findViewById(R.id.webview);

    webView.getSettings().setJavaScriptEnabled(true);
    webView.getSettings().setSupportZoom(false);

    //webview.loadUrl("www.google.com");

    webView.loadDataWithBaseURL("file:///android_asset/", "<img src=\"banner5.png\" height=\"98%\" width=\"100%\"/>", "text/html", "utf-8", null);



}

}

如何在同一个Activity onCreate（）中执行WebView和ListView？

3 个答案: