Question

我正在使用TomCat7和UBUNTU下的Eclipse运行我的项目我正在尝试在线学习教程以创建RESTful API。我遵循完全相同的步骤，但是当我尝试运行项目时遇到404错误。

这是我的.class文件，位于src文件夹中

package com.eviac.blog.restws;




import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;




/**
* 
* @author pavithra
* 
*/




// @Path here defines class level path. Identifies the URI path that 
// a resource class will serve requests for.
@Path("UserInfoService")
public class UserInfo {




// @GET here defines, this method will method will process HTTP GET
// requests.
@GET
// @Path here defines method level path. Identifies the URI path that a
// resource class method will serve requests for.
@Path("/name/{i}")
// @Produces here defines the media type(s) that the methods
// of a resource class can produce.
@Produces(MediaType.TEXT_XML)
// @PathParam injects the value of URI parameter that defined in @Path
// expression, into the method.
public String userName(@PathParam("i") String i) {




String name = i;
return "<User>" + "<Name>" + name + "</Name>" + "</User>";
}




@GET 
@Path("/age/{j}") 
@Produces(MediaType.TEXT_XML)
public String userAge(@PathParam("j") int j) {




int age = j;
return "<User>" + "<Age>" + age + "</Age>" + "</User>";
}
}

这是web-INF中的web.xml - ＆gt; LIB

<?xml version="1.0" encoding="UTF-8"?> 
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<display-name>RESTfulWS</display-name> 
<servlet> 
<servlet-name>Jersey REST Service</servlet-name> 
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class> 
<init-param> 
<param-name>com.sun.jersey.config.property.packages</param-name> 
<param-value>com.eviac.blog.restws</param-value> 
</init-param> 
<load-on-startup>1</load-on-startup> 
</servlet> 
<servlet-mapping> 
<servlet-name>Jersey REST Service</servlet-name> 
<url-pattern>/rest/*</url-pattern> 
</servlet-mapping> 
</web-app>

当我尝试从localhost访问它时，我收到错误..

请求的资源（/ RESTfulWS /）不可用。

Answer 1

您是否检查了控制台/日志，以确保您的网络应用已在tomcat中正确部署和启动？

您是否尝试过（GET）请求/ RESTfulWS / rest / UserInfoService / name / john

Answer 2

对于Jersey 2.x，ServletContainer的servlet类应为“org.glassfish.jersey.servlet.ServletContainer”，包的param-name应为“jersey.config.server.provider.packages”。

尝试

<servlet> 
<servlet-name>Jersey REST Service</servlet-name> 
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class> 
<init-param> 
<param-name>jersey.config.server.provider.packages</param-name> 
<param-value>com.eviac.blog.restws</param-value> 
</init-param> 
<load-on-startup>1</load-on-startup> 
</servlet>

错误404 - 请求的资源不可用 - Eclipse Tomcat7

2 个答案: