Question

我有以下字典，按值递增排序。

>>> x = {'foo': 2.01, 'bar': 4.11, 'qux':3.2, 'ail':1.2, 'dfa':0.03}
>>> sorted_x = sorted(x.iteritems(), key=operator.itemgetter(1))
>>> sorted_x
[('dfa', 0.029999999999999999), ('ail', 1.2), ('foo', 2.0099999999999998), ('qux', 3.2000000000000002), ('bar', 4.1100000000000003)]

如何按价值降序排序？我试过这个，但没有打印

>>> sorted_x.reverse()
>>>

Answer 1

您可以在排序时使用reverse=True：

>>> sorted(x.iteritems(), key=operator.itemgetter(1), reverse=True)

[('bar', 4.11), ('qux', 3.2), ('foo', 2.01), ('ail', 1.2), ('dfa', 0.03)]

Answer 2

In [143]:

import operator
x = {'foo': 2.01, 'bar': 4.11, 'qux':3.2, 'ail':1.2, 'dfa':0.03}
sorted_x = sorted(x.iteritems(), key=operator.itemgetter(1), reverse=True)
sorted_x
Out[143]:
[('bar', 4.11), ('qux', 3.2), ('foo', 2.01), ('ail', 1.2), ('dfa', 0.03)]

Answer 3

试试这个：

>>> x = {'foo': 2.01, 'bar': 4.11, 'qux':3.2, 'ail':1.2, 'dfa':0.03}
>>> sorted_x = sorted(x.iteritems(), key=operator.itemgetter(1), reverse=True)
>>> sorted_x
[('bar', 4.11), ('qux', 3.2), ('foo', 2.01), ('ail', 1.2), ('dfa', 0.03)]

按值对字典进行反向排序

3 个答案: