Question

arr = [
  [0, "Moving Companies", 10],
  [0, "ab-thera-sensa", 5],
  [0, "belt-center", 16],
  [0, "isabel", 3],
  [0, "kreatio", 2],
  [0, "service1", 7],
  [0, "sorbion-sachet-multi-star", 6],
  [0, "sss", 15],
  [0, "telecom-service-industry", 14],
  [1, " AbsoPad", 13],
  [1, "telecom-service", 8],
  [2, "cutisorb-ultra", 12],
  [2, "sorbion-contact", 11],
  [2, "sorbion-sachet-multi-star", 9]
]

假设这是我的数组，现在我想根据第一个元素按降序排序。我可以做arr.sort.reverse但问题现在就开始了

我把数组作为：

[
    [2, "sorbion-sachet-multi-star", 9],
    [2, "sorbion-contact", 11],
    [2, "cutisorb-ultra", 12],
    [1, "telecom-service", 8],
    [1, " AbsoPad", 13],
    [0, "telecom-service-industry", 14],
    [0, "sss", 15], [0, "sorbion-sachet-multi-star", 6],
    [0, "service1", 7],
    [0, "kreatio", 2],
    [0, "isabel", 3],
    [0, "belt-center", 16],
    [0, "ab-thera-sensa", 5],
    [0, "Moving Companies", 10]
]

现在，数组应该按照第二个元素的升序排序。

如何实现？

结果如下：

[
  [2, "cutisorb-ultra", 12],
  [2, "sorbion-contact", 11],
  [2, "sorbion-sachet-multi-star", 9],
  [1,.......]
]

Answer 1

使用块自定义排序。首先按第一个元素（0）进行降序排序。如果它们相等，则由第二个元素（1）进行升序排序：

arr.sort! do |a, b|
  result = b[0] <=> a[0]
  result = a[1] <=> b[1] if result == 0
  result
end

Answer 2

这个怎么样？

arr.sort { |i,j| [j[0],j[2]] <=> [i[0],i[2]]  }

输出：

=> [[2, "cutisorb-ultra", 12],
 [2, "sorbion-contact", 11],
 [2, "sorbion-sachet-multi-star", 9],
 [1, " AbsoPad", 13],
 [1, "telecom-service", 8],
 [0, "belt-center", 16],
 [0, "sss", 15],
 [0, "telecom-service-industry", 14],
 [0, "Moving Companies", 10],
 [0, "service1", 7],
 [0, "sorbion-sachet-multi-star", 6],
 [0, "ab-thera-sensa", 5],
 [0, "isabel", 3],
 [0, "kreatio", 2]]

Answer 3

请尝试：

arr.sort_by{|x|[-x[0],-x[2]]}

在Ruby on Rails中对数组进行排序

3 个答案: