Question

由于一个错误，我遇到了一些数据一致性问题。

现在我正在尝试对其进行排序，但不知何故，当我运行部分测试查询phpmyadmin崩溃或在很长一段时间内没有响应时。我试着自己运行嵌套的子查询，它们工作正常。

基本上我要解决的问题是：

如何从具有多个resource_type=1的所有用户中删除重复的geo_address FROM resource_type=1 FROM该用户还拥有geo_address resource_type=2的用户

基本上，这意味着如果用户有2 resource_type=1和1 resource_type=2，则他有resource_type=1重复。如果用户有2个resource_type=1但没有resource_type=2，那么它将落入我未在此处解决的不同情况。

我发现我的SQL查询

的逻辑很麻烦

到目前为止我得到的是这个，但我知道它的根本错误，因为它崩溃了

我如何正确构建查询？

SELECT member_num
  FROM geo_address2 
 WHERE     id IN (SELECT id 
                    FROM geo_address2 
                   WHERE resource_type=1 
                GROUP BY member_num 
                  HAVING COUNT(resource_type) > 1
        )
       AND id IN (SELECT id 
                    FROM geo_address2 
                   WHERE resource_type=2 
                GROUP BY member_num 
                  HAVING COUNT(resource_type) = 1 
        )

Answer 1

经过一番讨论后，我编辑了答案一种选择是使用此查询：

DELETE 
  FROM geo_address2
 WHERE id IN (SELECT DISTINCT g12.id
                FROM (SELECT member_num, 
                             id
                        FROM geo_address2 
                       WHERE resource_type = 1) g1
              JOIN 
                     (SELECT member_num, 
                             id
                        FROM geo_address2 
                       WHERE resource_type = 1) g12
                   ON g1.member = g12.member AND g1.id > g12.id
                     (SELECT member_num, 
                             id
                        FROM geo_address2 
                       WHERE resource_type = 2) g2
                   ON g1.member_num = g2.member_num
               );

第二个（我相信它在逻辑上是一样的）：

DELETE 
  FROM geo_address2
 WHERE id IN (
            SELECT g1.id
              FROM geo_address2 g0
                   JOIN geo_address2 g1
                        ON (g0.member_num = g1.member_num 
                            AND g0.id > g1.id
                            AND g0.resource_type = 1
                            AND g1.resource_type = 1)
                   JOIN geo_address2 g2
                        ON (g1.member_num = g2.member_num
                            AND g0.resource_type = 1
                            AND g2.resource_type = 2)
               );

Answer 2

DELETE dupe
FROM   geo_address2 dupe
  JOIN geo_address2 keep
    ON dupe.id > keep.id
   AND dupe.member_num = keep.member_num
   AND dupe.resource_type = keep.resource_type
  JOIN geo_address2 save
    ON save.member_num = dupe.member_num
   AND save.resource_type = 2
WHERE  dupe.resource_type = 1

SQL查询崩溃PHPMYADMIN - 查询逻辑问题

2 个答案: