修复：消息102，级别15，状态1，行37错误的语法附近＆＃39;）＆＃39;

Question

我正在使用MS SQL服务器。

我在查询中使用了 pivot 。我已经完成的工作如下：

SQL过程

--/*==========================================================
--
--
--
--===========================================================*/

--CREATE VIEW View_BASequenceExportDtl
--AS

--ALTER PROCEDURE Proc_BASequenceExportDtl 

--AS

DECLARE @cols NVARCHAR(MAX)
DECLARE @stmt NVARCHAR(MAX)


SET @cols = ISNULL(@cols + ', ', '') (
                                            SELECT Table3.vAnalyteName
                                            FROM Table3,BaSequenceScheduleHdr,BAAnalyteSampleHdr
                                            WHERE Table3.nTable2No = BaSequenceScheduleHdr.nTable2No
                                                  AND Table3.cStatusIndi <> 'D'
                                     )

SET @stmt = 'SELECT     
            Table1.nBaSequenceScheduleHdrNo,
            Table1.vSampleId,
            Table1.vSampleName,
            Table1.iSeqNo,
            Table1.vSampleType,
            Table2.vInjectionVolume,
            Table3.vAnalyteName,
            Table4.nConcentration,
            Table1.cStatusIndi

        FROM Table1

                INNER JOIN BaSequenceScheduleHdr
                      ON(BaSequenceScheduleHdr.nBaSequenceScheduleHdrNo =  Table1.nBaSequenceScheduleHdrNo
                         AND BaSequenceScheduleHdr.cStatusIndi <> ''D'')

                INNER JOIN Table2
                      ON(Table2.nTable2No = BaSequenceScheduleHdr.nTable2No
                         AND Table2.cStatusIndi <> ''D'')

                INNER JOIN Table3
                      ON(Table3.nTable2No = BaSequenceScheduleHdr.nTable2No
                         AND Table3.cStatusIndi <> ''D'')          

                LEFT JOIN BAAnalyteSampleHdr
                     ON(BAAnalyteSampleHdr.nTable2No = BaSequenceScheduleHdr.nTable2No
                        AND BAAnalyteSampleHdr.nTable3No = Table3.nTable3No
                        AND BAAnalyteSampleHdr.cStatusIndi <> ''D'')          

                LEFT JOIN Table4
                     ON(Table4.nBAAnalyteSampleHdrNo = BAAnalyteSampleHdr.nBAAnalyteSampleHdrNo
                        AND Table4.vSampleID =  Table1.vSampleId
                        AND Table4.cStatusIndi <> ''D'')

        PIVOT (
                SUM(Table4.nConcentration) FOR Table3.vAnalyteName IN ( ' + @cols + ' )
              ) AS PVT'

exec(@stmt)

在过程中使用Pivot的原因

此处concentration取决于Analyte。所以我想要的是，根据动态Analyte名称，其concentration应位于该列之下。

它应该如何工作

在此处，首先@cols将包含将传递给 analyte 的所有PIVOT个名称。最终的 exec(@stmt) 应该将所有数据作为 View

返回

---

但我收到错误： (10 row(s) affected) Msg 102, Level 15, State 1, Line 37 Incorrect syntax near ')'.

而且，我第一次使用 pivot 。所以，如果有任何错误，请告诉我。

Answer 1

这部分没有意义

SET @cols = ISNULL(@cols + ', ', '') (
                                            SELECT Table3.vAnalyteName
                                            FROM Table3,BaSequenceScheduleHdr,BAAnalyteSampleHdr
                                            WHERE Table3.nTable2No = BaSequenceScheduleHdr.nTable2No
                                                  AND Table3.cStatusIndi <> 'D'
                                     )

Answer 2

构建以逗号分隔的列列表的方式需要更改。将其更改为：

DECLARE @cols NVARCHAR(MAX) = N''

SELECT @cols = @cols + N', ' + Table3.vAnalyteName
FROM Table3,BaSequenceScheduleHdr,BAAnalyteSampleHdr
WHERE Table3.nTable2No = BaSequenceScheduleHdr.nTable2No
AND Table3.cStatusIndi <> 'D'

set @cols = stuff(@cols, 1, 2, N'')