Question

我有这个阵列：

$test = array(1,2,3,4,5,6);
foreach($test as $index => $value){
   echo $value . $next;
   // how to get the next one after the $value ??
}

所以我的显示应该是：

1 2
2 3
3 4
..
..

如何在foreach循环中获得下一个值？

Answer 1

如下所示，但请记住，你的foreach将在最后一轮打印6只：）

$test = array(1,2,3,4,5,6);
foreach($test as $index => $value){
   echo $value . $test[$index+1];
}

Answer 2

试试这个

$test = array(1,2,3,4,5,6);
$len = count($test);
foreach($test as $index => $value){
    if($test[$index+1] != ''  && $test[$index] != '')
       echo $value . $test[$index+1].'<br>';
}

Answer 3

你可以记住最后一个值并以这种方式工作：

$test = array(1,2,3,4,5,6);
$last = null;
foreach($test as $index => $next){
  if(!is_null($last)) {
    echo $last . $next;
  }
  $last = $next;
}

即使您的索引不是数字，也可以使用，即如果它是：

array(
'Peter' => 'Jackson',
'Steve' => 'McQueen',
'Paul' => 'McCartney',
'April' => 'Ludgate'
);

Answer 4

试试这段代码

$test = array(1,2,3,4,5,6);
foreach($test as $index => $value){
   if(end($test) == $test[$index+1]) {  
   echo $value . $test[$index+1];
   break;
  }
  else {
 echo $value . $test[$index+1];
 }
}

Answer 5

试试这个

<?php
$test = array(1,2,3,4,5,6);

foreach($test as $value)
{
   echo $value;

   // We have advanced our array pointer. So next is already current
   $next = current($test);

   // If there is no next, it will return FALSE
   if($next)
      echo ' '.$next.'<br />';

   // Advance array pointer by one
   next($test);
}
?>

输出

如何在数组循环中获取下一个值？

5 个答案: