String s[];
System.out.println("Enter loop value");
int t = s.nextInt();
for(int i=0;i<t;i++)
{
str[i]=s.nextLine();
}
虽然它读取它会给出空指针异常
答案 0 :(得分:2)
你需要的是这样的东西:
Scanner s = new Scanner(System.in);
System.out.println("Enter loop value");
int t = s.nextInt(); // read number of element
s.nextLine(); // consume new line
String str[] = new String[t];
for(int i=0;i<t;i++)
{
str[i]=s.nextLine();
}
System.out.println(Arrays.toString(str));
希望这有帮助。
答案 1 :(得分:0)
尝试这样的事情:
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter loop value");
String a[] = new String[Integer.parseInt(br.readLine())];
for (int i = 0; i < a.length; i++) {
a[i] = br.readLine();
}
答案 2 :(得分:0)
我更改了代码中的拼写错误和遗漏声明:
package snippet;
import java.io.IOException;
import java.util.Arrays;
import java.util.Scanner;
public class Snippet {
public static void main(String[] args) throws IOException {
Scanner s = new Scanner(System.in);
String str[] = new String[10];
System.out.println("Enter loop value (maximum 9)");
int t = s.nextInt();
for (int i = 0; i <= t; i++) {
str[i] = s.nextLine();
}
System.out.println("your entered lines:");
System.out.println(Arrays.toString(str));
}
}
但是,我建议将值存储在List
而不是Array
中。我还希望使用BufferedReader
来使用Scanner
。
答案 3 :(得分:0)
//After modifying my code works well
import java.io.*;
import java.util.Scanner;
class Sample
{
public static void main(String[] args) throws Exception
{
bufferedReader();
scanner();
}
static void bufferedReader()throws Exception{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter Number of Strings");
int len = Integer.parseInt(br.readLine());
String a[] = new String[len];
for(int i=0; i<len; i++){
System.out.println("Enter String"+ (i+1));
a[i] = br.readLine();
}
for(String str : a)
System.out.println(str);
}
static void scanner(){
Scanner s = new Scanner(System.in);
System.out.println("Enter Number of Strings");
int len = Integer.parseInt(s.nextLine());
String a[] = new String[len];
for(int i=0; i<len; i++){
System.out.println("Enter String"+ (i+1));
a[i] = s.nextLine();
}
for(String str : a)
System.out.println(str);
}
}
但是当使用Scanner时,nextLine()会在读取时跳过数据 如果有人知道请用例子发表说明