Question

我有一些大型CSV文件，格式如下（以逗号分隔）

2014.03.11 14:59:59.146,67.1547,67.15507,0.02,0.02
2014.03.11 14:59:59.206,67.15405,67.15437,0.02,0.02
2014.03.11 14:59:59.506,67.15552,67.15589,0.02,0.02
2014.03.11 14:59:59.707,67.15581,67.15616,0.02,0.02

现在我想完成这项任务。

多数100到第2列和第3列

结果应该是

2014.03.11 14:59:59.146,6715.47,6715.507,0.02,0.02
2014.03.11 14:59:59.206,6715.405,6715.437,0.02,0.02
2014.03.11 14:59:59.506,6715.552,6715.589,0.02,0.02
2014.03.11 14:59:59.707,6715.581,6715.616,0.02,0.02

非常感谢帮助。感谢

Answer 1

此awk应该：

awk '{$2*=100;$3*=100}1' FS=, OFS=, file
2014.03.11 14:59:59.146,6715.47,6715.51,0.02,0.02
2014.03.11 14:59:59.206,6715.4,6715.44,0.02,0.02
2014.03.11 14:59:59.506,6715.55,6715.59,0.02,0.02
2014.03.11 14:59:59.707,6715.58,6715.62,0.02,0.02

您可以使用$2=$2*100或$2*=100将列乘以100

Answer 2

perl -F/,/ -lape "$F[$_] *= 100 for (1,2); $_ = join',', @F;" < input.csv > output.csv

在大型CSV文件中搜索和修改列

2 个答案: