在整个sql server数据库中搜索字符串

时间:2014-03-12 05:56:28

标签: sql-server

我想在整个数据库中搜索字符串或int。比如我想搜索“管理员”。在数据库中。为此,我该怎么办?

谢谢, kibria

2 个答案:

答案 0 :(得分:1)

Try this stored procedure


CREATE PROC SearchAllTables
    (
        @SearchStr nvarchar(100)
    )
    AS
    BEGIN

        CREATE TABLE #Results (ColumnName nvarchar(370), ColumnValue nvarchar(3630))

        SET NOCOUNT ON

        DECLARE @TableName nvarchar(256), @ColumnName nvarchar(128), @SearchStr2 nvarchar(110)
        SET  @TableName = ''
        SET @SearchStr2 = QUOTENAME('%' + @SearchStr + '%','''')

        WHILE @TableName IS NOT NULL

        BEGIN
            SET @ColumnName = ''
            SET @TableName = 
            (
                SELECT MIN(QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME))
                FROM     INFORMATION_SCHEMA.TABLES
                WHERE         TABLE_TYPE = 'BASE TABLE'
                    AND    QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME) > @TableName
                    AND    OBJECTPROPERTY(
                            OBJECT_ID(
                                QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME)
                                 ), 'IsMSShipped'
                                   ) = 0
            )

            WHILE (@TableName IS NOT NULL) AND (@ColumnName IS NOT NULL)

            BEGIN
                SET @ColumnName =
                (
                    SELECT MIN(QUOTENAME(COLUMN_NAME))
                    FROM     INFORMATION_SCHEMA.COLUMNS
                    WHERE         TABLE_SCHEMA    = PARSENAME(@TableName, 2)
                        AND    TABLE_NAME    = PARSENAME(@TableName, 1)
                        AND    DATA_TYPE IN ('char', 'varchar', 'nchar', 'nvarchar', 'int', 'decimal')
                        AND    QUOTENAME(COLUMN_NAME) > @ColumnName
                )

                IF @ColumnName IS NOT NULL

                BEGIN
                    INSERT INTO #Results
                    EXEC
                    (
                        'SELECT ''' + @TableName + '.' + @ColumnName + ''', LEFT(' + @ColumnName + ', 3630) 
                        FROM ' + @TableName + ' (NOLOCK) ' +
                        ' WHERE ' + @ColumnName + ' LIKE ' + @SearchStr2
                    )
                END
            END    
        END

        SELECT ColumnName, ColumnValue FROM #Results
    END

答案 1 :(得分:0)