已经拥有的android aws错误代码桶

Question

我有一个Android应用程序，其功能是将图像上传到AWS（亚马逊网络服务）S3。当我第一次成功运行此应用程序图像上传时。但是当我第二次上传图片时，我收到了以下错误。我该如何解决这个错误？

这是错误：

这是我的活动：

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    // getActionBar().setDisplayShowTitleEnabled(false);
    this.requestWindowFeature(Window.FEATURE_NO_TITLE);
    s3Client.setRegion(Region.getRegion(Regions.US_WEST_2));
    setContentView(R.layout.submit);

    submit = (Button) findViewById(R.id.buttonsubmit);
    submit.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub

            Uri selectedImage = Uri.parse(Environment
                    .getExternalStorageDirectory().getPath()
                    + File.separator
                    + "Pictures"
                    + File.separator
                    + "Spike" + File.separator + "cubicasa.jpg");

            new S3PutObjectTask().execute(selectedImage);



        }
    });

}
private class S3PutObjectTask extends AsyncTask<Uri, Void, S3TaskResult> {

    ProgressDialog dialog;

    protected void onPreExecute() {
        dialog = new ProgressDialog(SubmitActivity.this);
        dialog.setMessage(SubmitActivity.this.getString(R.string.uploading));
        dialog.setCancelable(false);
        dialog.show();
    }

    protected S3TaskResult doInBackground(Uri... uris) {



        if (uris == null || uris.length != 1) {
            return null;
        }

        // The file location of the image selected.
        String filepath = Environment.getExternalStorageDirectory()
                .toString()
                + File.separator
                + "Pictures"
                + File.separator
                + "Spike" + File.separator + "cubicasa.jpg";
        Uri selectedImage = Uri.fromFile(new File(filepath));
        // Uri selectedImage =
        // Uri.parse("content://media/external/images/media/40894");

        String URLLLLLLLLL = selectedImage.toString();
        Log.e("uRLLLLLLLLLLLLLL", URLLLLLLLLL);
        ContentResolver resolver = getContentResolver();

        ObjectMetadata metadata = new ObjectMetadata();
        metadata.setContentType(resolver.getType(selectedImage));

        S3TaskResult result = new S3TaskResult();

        // Put the image data into S3.
        try {
            s3Client.createBucket(Constants.getPictureBucket());

            PutObjectRequest por = new PutObjectRequest(
                    Constants.getPictureBucket(), Constants.PICTURE_NAME,
                    resolver.openInputStream(selectedImage), metadata);
            s3Client.putObject(por);
        } catch (Exception exception) {

            result.setErrorMessage(exception.getMessage());
        }

        return result;
    }

    protected void onPostExecute(S3TaskResult result) {

        dialog.dismiss();

        if (result.getErrorMessage() != null) {

            displayErrorAlert(
                    SubmitActivity.this
                            .getString(R.string.upload_failure_title),
                    result.getErrorMessage());
        } else {
            Toast toast = Toast.makeText(getApplicationContext(),
                    "Uploaded Successfully", Toast.LENGTH_SHORT);
            toast.show();

        }
    }
}

这是我的常数类：

public class Constants {

public static final String ACCESS_KEY_ID = "accesskey";
public static final String SECRET_KEY = "secretkey";

public static final String PICTURE_BUCKET = "picture-bucket5";
public static final String PICTURE_NAME = "NameOfThePicture5";


public static String getPictureBucket() {
    return ("bd.dse.test" + ACCESS_KEY_ID + PICTURE_BUCKET).toLowerCase(Locale.US);
}

任何帮助将不胜感激。提前谢谢。

Answer 1

从您的代码：您每次都在创建存储桶，不要那样会导致存储桶重复。使用名称（字符串）创建一次桶，如下面的代码。

s3Client.createBucket("images");

下次在病房中不要在你的代码中调用这个创建存储桶，只需将图像放在该存储桶中就像下面的代码一样。

S3.createObjectForBucket("images", Token, _Image);