Question

我正在尝试让我的系统允许在单击超链接时下载文件。下面的代码显示有关要下载的文件的信息，此信息是从数据库中收集的。

代码显示在表中，单击超链接时应进行下载。变量＆＃34; $ file＆＃34;包含存储在数据库中的文件路径。单击此按钮时，应启动download.php文件，该文件应允许下载文件。但是，打开白页而没有任何反应。

YourPurchases.php

if (count($reports) != 0) {    
    foreach ($reports as $report) {     
        $title = $report['reportID'];
        $rep_ID = $report['reportName'];
        $reportSubCat = $report['subcategoryName'];
        $uploadedBy = $report['userID'];
        $numPages = $report['pageTotal'];
        $file = $report['location']; // this is the file path stored in the database

        $purchasedreportstable .= '<table>
                                       <tr>
                                           <th>Report ID &nbsp</th>
                                           <th>Report Name &nbsp </th>
                                           <th>Report SubCategory &nbsp </th>
                                           <th>Uploaded By &nbsp </th>
                                           <th>Page Total &nbsp</th>
                                           <th>Download </th>
                                       </tr>
                                       <tr>
                                           <td>'.$title.'</td>
                                           <td>'.$rep_ID.'</td>
                                           <td>'.$reportSubCat.'</td>
                                           <td>'.$uploadedBy.'</td>
                                           <td>'.$numPages.'</td>
                                           <td> <a href="download.php file='.$file.'">Download</a>
                                       </tr>';
    }
    $purchasedreportstable .= '</table>';      
               ;                                            
    echo $purchasedreportstable;

的download.php

<?php
    function downloadFile($file,$speed=1024){
        if (file_exists($file)) {
            if(is_dir($file)){return 'isdir';}
                header('Content-Description: File Transfer');
                header('Content-Type: application/octet-stream');
                header('Content-Disposition: attachment; filename="'.basename($file).'"');
                header('Content-Transfer-Encoding: binary');
                header('Connection: Keep-Alive');
                header('Expires: 0');
                header('Cache-Control: must-revalidate, post-check=0, pre-check=0');
                header('Pragma: public');
                header('Content-Length: '.sprintf("%u", filesize($file)));

                ob_clean();
                $handle = fopen($file, "rb");
                $chunksize=(sprintf("%u", filesize($file))/$speed);

                set_time_limit(0);
                while (!feof($handle)) {
                    echo fgets($handle, $chunksize);
                    flush();
                }
            fclose($handle);
            die;
        }else{
                return false;
        }
        return;
    }
?>

数据库中的文件路径类似于 reports / upload1_60b7d515219902288b.pdf

非常感谢任何帮助，

由于

Answer 1

根据您发布的内容判断，预计会出现空白屏幕，因为您的download.php代码是一个永远称为的函数。

尝试把它放在底部：

downloadFile($_GET['file']);

如果返回false，您可能还需要检查返回值：

if(!downloadFile($_GET['file']))
    echo 'Error encountered when trying to download file!';

Answer 2

在download.php中，您需要先从URL获取文件名。您正在生成指向该页面的链接，但从不从URL中触发文件名或触发该功能。此代码低于函数的最后一个括号。

if (isset($_GET['file'])) {
    $file = $_GET['file']
}

$result = downloadFile($file);

if ($result == FALSE) {
    echo "Sorry, file does not exist.";
}

PHP文件下载失败

2 个答案: