Question

检查这个小提琴http://jsfiddle.net/robincox/9nNej/34/，问题出在javaScript部分。或者您可以在此代码中看到它：

$(".off-canvas-list li:not(:has(ul))").addClass("liLast");
$(".off-canvas-list li").has("ul").addClass("liHasChild");
$("li.liHasChild > a").click(
    function () {

        if ($(this).siblings("ul").hasClass("opened")) {

            // Here I want to find the sibling ul tag to the a tag I clicked.
            // Then I want to check that ul tags children after an li with the class "liHasChild".
            // If such a tag isn't found the value of 1 shall be stored in a variable named depth.
            // If such a tag is found (an li with the class "liHasChild") then search it's child
            // ul tag after an li with the class "liHasChild"
            // If such a tag isn't found the value of 2 shall be stored in a variable named depth.

        } else {

            // Open clicked a tags sibling ul

            $(this).siblings("ul").slideDown();
            $(this).siblings("ul").addClass("opened");

        }

    }
);

$(".off-canvas-list ul").css("display", "none");

Answer 1

尝试以下递归函数：

function depthOf(elem){
    var $children = $(elem).siblings("ul").children("li.liHasChild"); 
    if($children.length){ //If there are children with children
        return 1 + depthOf($children.find("a")); //count and go deeper
    }
    return 1;
}

以下是如何使用它：

if ($(this).siblings("ul").hasClass("opened")) {
    alert(depthOf(this));
}

在列表中查找最后ul的深度

1 个答案: