Question

我有以下Makefile：

CC=g++
CFLAGS=-c -pedantic -std=c++11 -lglfw -lGL -lGLU -lX11 -lXxf86vm -lXrandr -lpthread -lXi

all: Set GLDrawableGraph Edge Graph Play main

Set: Set.cpp Set.h
        $(CC) $(CFLAGS) -o Set Set.cpp

GLDrawableGraph:  GLDrawableGraph.cpp GLDrawableGraph.h Edge.h Graph.h 
         $(CC) $(CFLAGS) -o GLDrawableGraph GLDrawableGraph.cpp

Edge:  Edge.cpp Edge.h
         $(CC) $(CFLAGS) -o Edge Edge.cpp

Graph:  Graph.cpp GLDrawableGraph.h Edge.h Graph.h Play.h
         $(CC) $(CFLAGS) -o Graph Graph.cpp

Play:  Play.cpp GLDrawableGraph.h Edge.h Graph.h  Play.h
         $(CC) $(CFLAGS) -o Play Play.cpp

main:  main.cpp GLDrawableGraph.o Edge.o Graph.o Play.o GLDrawableGraph.h Edge.h Graph.h Play.h Set.o Set.h
         $(CC) $(CFLAGS) -o main main.cpp GLDrawableGraph.cpp Edge.cpp Graph.cpp Play.cpp Set.cpp

我得到以下输出：

GLDrawableGraph.cpp:95:10: error: ‘p’ does not name a type
     auto p=nodes.find(nodenumber);
          ^
GLDrawableGraph.cpp:96:8: error: ‘p’ was not declared in this scope
     if(p==nodes.end()) throw std::string("Tried to color nonexistant vertex");
        ^
GLDrawableGraph.cpp:97:5: error: ‘p’ was not declared in this scope
     p->second.color=col;
     ^
GLDrawableGraph.cpp: In member function ‘void DrawableGraph::DrawGraph(GLFWwindow*) const’:
GLDrawableGraph.cpp:140:15: error: ISO C++ forbids declaration of ‘e’ with no type [-fpermissive]
     for(auto &e : edges) {
               ^
GLDrawableGraph.cpp:140:19: error: range-based ‘for’ loops are not allowed in C++98 mode
     for(auto &e : edges) {
                   ^
GLDrawableGraph.cpp:141:18: error: request for member ‘first’ in ‘e’, which is of non-class type ‘int’
         int i1=e.first.first;
                  ^
GLDrawableGraph.cpp:142:18: error: request for member ‘first’ in ‘e’, which is of non-class type ‘int’
         int i2=e.first.second;
                  ^
GLDrawableGraph.cpp:151:28: error: request for member ‘second’ in ‘e’, which is of non-class type ‘int’
         RGB rgb=RGBColor(e.second.color);
                            ^
GLDrawableGraph.cpp:158:15: error: ISO C++ forbids declaration of ‘p’ with no type [-fpermissive]
     for(auto &p : nodes) {
               ^
GLDrawableGraph.cpp:158:19: error: range-based ‘for’ loops are not allowed in C++98 mode
     for(auto &p : nodes) {
                   ^
GLDrawableGraph.cpp:159:26: error: request for member ‘second’ in ‘p’, which is of non-class type ‘int’
         float xx=float(p.second.x-R.l)/(R.r-R.l)*1.8-0.9;
                          ^
GLDrawableGraph.cpp:160:26: error: request for member ‘second’ in ‘p’, which is of non-class type ‘int’
         float yy=float(p.second.y-R.b)/(R.t-R.b)*1.8-0.9;

我认为这些错误来自C ++ 11与常规C ++的差异，但我已经给出了-std = c ++ 11选项，但它仍然不起作用。

Answer 1

您的makefile依赖项不正确。会发生的是它使用内置规则编译项目，因此您的标志不适用，编译器无法识别C ++ 11 auto关键字。尝试使用make -r进行编译以禁用内置规则并查看会发生什么。

你可能想要这样的东西：

CXX := g++
CPPLAGS := -Wall -Wextra
CXXFLAGS := -std=c++11
LDLIBS := -lglfw -lGL -lGLU -lX11 -lXxf86vm -lXrandr -lpthread -lXi

all : main

main : main.o GLDrawableGraph.o Edge.o Graph.o Play.o Set.o 
    ${CXX} -o $@ $^ ${LDLIBS}

%.o : %.cpp # also auto-generates dependencies
    ${CXX} -c -o $@ ${CPPLAGS} ${CXXFLAGS} -MD -MP -MF ${@:.o=.d} $<

-include $(wildcard *.d) # include auto-generated dependencies

为什么这个Makefile没有正确编译？

1 个答案: