Question

我对IOS开发真的很陌生。我想开发一个应用程序，它处理一些Web服务并在表视图中显示。不知何故，我找到了第三方库来做网络的东西[AFNetworking 2]。下面是我获取任何给定网址和参数的json响应的代码。

-(NSDictionary*)getWebServiceResponce:(NSString *)url :(NSDictionary *)object
{

   // NSDictionary *parameters = [[NSDictionary alloc] initWithObjectsAndKeys:@"47", @"caregiverPersonId", nil];
  __block NSDictionary* result=Nil;
  __block NSString* person=Nil;


    AFSecurityPolicy *policy = [[AFSecurityPolicy alloc] init];
    [policy setAllowInvalidCertificates:YES];

    AFHTTPRequestOperationManager *operationManager = [AFHTTPRequestOperationManager manager];
    [operationManager setSecurityPolicy:policy];
    operationManager.requestSerializer = [AFJSONRequestSerializer serializer];
    operationManager.responseSerializer = [AFJSONResponseSerializer serializer];

    [operationManager POST:url
                parameters:object
                   success:^(AFHTTPRequestOperation *operation, id responseObject) {


                     NSLog(@"JSON: %@", [responseObject description]);
                       person = [responseObject[@"d"]objectForKey:@"PersonId"];
                     //  [self returnedResponce:responseObject];
                       result = (NSDictionary *) responseObject[@"d"];
                        NSLog(@"RESULT: %@", result);
                        NSLog(@"personm: %@", person);
                       [operation waitUntilFinished];
                   }
                   failure:^(AFHTTPRequestOperation *operation, NSError *error) {
                       NSLog(@"Error: %@", [error description]);
                       //result = [error];
                   }
     ];

    return result;
    }

这段代码完美无缺..但我的观点是，当我放置一些断点来检查我为几个变量得到的值时，它显示为null。但是我的日志显示了整个json响应。

我希望将我的响应对象作为字典返回。因为我想用回复做一些过程..有人可以帮我这个吗？

Answer 1

问题是result在返回时为零。 AFNetworking使用ObjC的强大块，它们以异步方式执行。 Read more about it here

您应该在getWebServiceResponce方法中包含一个回调块。我把一些代码放在一起，但你应该真正阅读更多关于块的内容。

-(void)webServiceResponceForURL:(NSString *)url dictionary:(NSDictionary *)object success:(void (^)(NSDictionary *responseObject))success {
// NSDictionary *parameters = [[NSDictionary alloc] initWithObjectsAndKeys:@"47", @"caregiverPersonId", nil];
__block NSDictionary* result=Nil;
__block NSString* person=Nil;

AFSecurityPolicy *policy = [[AFSecurityPolicy alloc] init];
[policy setAllowInvalidCertificates:YES];

AFHTTPRequestOperationManager *operationManager = [AFHTTPRequestOperationManager manager];
[operationManager setSecurityPolicy:policy];
operationManager.requestSerializer = [AFJSONRequestSerializer serializer];
operationManager.responseSerializer = [AFJSONResponseSerializer serializer];
[operationManager POST:url
            parameters:object
               success:^(AFHTTPRequestOperation *operation, id responseObject) {
                   NSLog(@"JSON: %@", [responseObject description]);
                   person = [responseObject[@"d"]objectForKey:@"PersonId"];
                   //  [self returnedResponce:responseObject];
                   result = (NSDictionary *) responseObject[@"d"];
                   NSLog(@"RESULT: %@", result);
                   NSLog(@"personm: %@", person);

                   //We are executing the block as soon as we have the results.
                   if (success) {
                       success(responseObject);
                   }
               }
               failure:^(AFHTTPRequestOperation *operation, NSError *error) {
                   NSLog(@"Error: %@", [error description]);
                   //result = [error];
               }
 ];
}

编辑：

[self webServiceResponceForURL:@"foo://foo" dictionary:nil success:^(NSDictionary *responseObject) {
    //your code here
}

Answer 2

[self webServiceResponceForURL:@"foo://foo" dictionary:nil success:^(NSDictionary *responseObject) {
    //your code here
}

在这里，您将获得NSDictionary格式的完整responseObject。您可以将responseObject分配给实例变量。现在，此实例变量将在点时使用。在你的情况下，它将传递按钮事件。

使用AFNetworking处理响应2

2 个答案: