我想从Involvement列中仅包含Amanda和Dina的每个组(EID)中选择数据。 这是我的表数据
EID Ename EPrice Involvement
1 Breakfast 60 Amanda
1 Breakfast 60 Dina
2 Dinner 50 Nick
2 Dinner 50 Dina
2 Dinner 50 Amanda
2 Dinner 50 Jessica
我想要一个结果
EID Ename EPrice Involvement
1 Breakfast 60 Amanda
1 Breakfast 60 Dina
我不希望EID = 2的结果,因为它包含NICK和JESSICA
答案 0 :(得分:3)
select * from your_table
where eid in
(
select eid
from your_table
group by eid
having sum(case when involvement not in ('Amanda','Dina') then 1 else 0 end) = 0
)
and involvement in ('Amanda','Dina')