Question

有人可以解释一下这个查询有什么问题吗？

SELECT Attempts, (CASE WHEN LastLogin IS NOT NULL AND DATE_ADD(LastLogin, INTERVAL 1 MINUTE)>NOW() THEN 1 ELSE 0) AS Denied 
FROM tbl_loginLocks 
WHERE IP = "192.168.178.43";

我收到一条操作丢失的错误。任何帮助，将不胜感激。谢谢！

Answer 1

您在END：

的末尾遗失CASE

SELECT Attempts, (CASE WHEN LastLogin IS NOT NULL AND DATE_ADD(LastLogin, INTERVAL 1 MINUTE)>NOW() THEN 1 ELSE 0 END) AS Denied 
FROM tbl_loginLocks 
WHERE IP = '192.168.178.43';

或者，使用IIF声明：

SELECT Attempts, IIF(LastLogin IS NOT NULL AND DATEADD("n", 1, LastLogin) >NOW(), 1, 0) AS Denied 
FROM tbl_loginLocks 
WHERE IP = '192.168.178.43';

Answer 2

在 CASE 声明的末尾添加结束

Date_Add 功能错误

Microsoft Access DateAdd 函数返回添加了特定时间/日期间隔的日期。

<强>语法

Microsoft Access DateAdd函数的语法是：

DateAdd ( interval, number, date )

试试这个

SELECT Attempts, (CASE WHEN LastLogin IS NOT NULL AND DateAdd ("n",1,LastLogin)>NOW() THEN 1 ELSE 0 END) AS Denied 
FROM tbl_loginLocks 
WHERE IP = "192.168.178.43";

Answer 3

MS Access没有案例陈述，请使用IIF：

SELECT Attempts, 
IIf(Not IsNull(LastLogin) AND DATEADD("n",1,LastLogin)>NOW(),1,0) AS Denied 
FROM tbl_loginLocks 
WHERE IP = "192.168.178.43"

Dateadd
IIF

MS Access查询无法正常工作

3 个答案: