将字节数组转换为mp3文件

时间:2014-03-11 07:47:08

标签: android audio android-audiorecord

我在android中编写了一个应用程序,用于记录来自麦克风的语音,并使用

将其存储在字节数组中
audioRecord.read(bigBuff, currSize, minBuffSize);

bigBuff是一个字节数组现在我想把这个字节数组转换成.mp3文件或.wav文件我这样做

File f = new File(Environment.getExternalStorageDirectory().getAbsolutePath()+"/aaa.wav");

f.createNewFile();
FileOutputStream fos = new FileOutputStream(f);
fos.write(bigBuff);
fos.flush();
fos.close();

aaa.wav文件已成功创建,但当我尝试从应用程序外部播放时,像任何其他.wav或.mp3文件一样,显示错误“抱歉播放器不支持此类型的音频文件”

请帮忙。

2 个答案:

答案 0 :(得分:1)

我认为你没有输入数据标题 添加此方法和复制数据后。

        private void WriteWaveFileHeader(
                    FileOutputStream out, long totalAudioLen,
                    long totalDataLen, long longSampleRate, int channels,
                    long byteRate) throws IOException {

            byte[] header = new byte[44];

            header[0] = 'R';  // RIFF/WAVE header
            header[1] = 'I';
            header[2] = 'F';
            header[3] = 'F';
            header[4] = (byte) (totalDataLen & 0xff);
            header[5] = (byte) ((totalDataLen >> 8) & 0xff);
            header[6] = (byte) ((totalDataLen >> 16) & 0xff);
            header[7] = (byte) ((totalDataLen >> 24) & 0xff);
            header[8] = 'W';
            header[9] = 'A';
            header[10] = 'V';
            header[11] = 'E';
            header[12] = 'f';  // 'fmt ' chunk
            header[13] = 'm';
            header[14] = 't';
            header[15] = ' ';
            header[16] = 16;  // 4 bytes: size of 'fmt ' chunk
            header[17] = 0;
            header[18] = 0;
            header[19] = 0;
            header[20] = 1;  // format = 1
            header[21] = 0;
            header[22] = (byte) channels;
            header[23] = 0;
            header[24] = (byte) (longSampleRate & 0xff);
            header[25] = (byte) ((longSampleRate >> 8) & 0xff);
            header[26] = (byte) ((longSampleRate >> 16) & 0xff);
            header[27] = (byte) ((longSampleRate >> 24) & 0xff);
            header[28] = (byte) (byteRate & 0xff);
            header[29] = (byte) ((byteRate >> 8) & 0xff);
            header[30] = (byte) ((byteRate >> 16) & 0xff);
            header[31] = (byte) ((byteRate >> 24) & 0xff);
            header[32] = (byte) (2 * 16 / 8);  // block align
            header[33] = 0;
            header[34] = RECORDER_BPP;  // bits per sample
            header[35] = 0;
            header[36] = 'd';
            header[37] = 'a';
            header[38] = 't';
            header[39] = 'a';
            header[40] = (byte) (totalAudioLen & 0xff);
            header[41] = (byte) ((totalAudioLen >> 8) & 0xff);
            header[42] = (byte) ((totalAudioLen >> 16) & 0xff);
            header[43] = (byte) ((totalAudioLen >> 24) & 0xff);

            out.write(header, 0, 44);
    }

答案 1 :(得分:0)

要配置标题,请参阅以下链接

https://ccrma.stanford.edu/courses/422/projects/WaveFormat/

http://www.topherlee.com/software/pcm-tut-wavformat.html

上面的标题对我来说不起作用,但在对配置进行微小更改后,它可以正常工作。