如何在没有半引号的情况下解析json数据

时间:2014-03-11 06:21:58

标签: javascript php jquery json

您好我正在尝试使用php json构建地图,当我尝试将值传递给javascript时显示错误

未捕获的SyntaxError:意外的令牌a

  {
            "map": "worldLow",
            "linkToObject": "Sharjah",
            "images": [{
                "id": "Sharjah",
                "color": "#000000",
                 svgPath: targetSVG,//error in this section as it is not passed without double quotes
                "title": "Sharjah",
                "latitude": "25.340225",
                "longitude": "55.395813",
                "scale": 1.5,
                "zoomLevel": 1.36,
                "zoomLongitude": -19.1341,
                "zoomLatitude": 49.1712,
    "lines": [ {
      "Projectname": "masjid",
      "latitudes": 12.2392,
      "longitudes": -0.84000000
     }
    ]},
     {
      svgPath: targetSVG,//error in this section as it is not passed without double quotes
      "Projectname": "masjid",
      "latitude": 12.2392,
      "longitude": -0.84000000,
    "selectable": "true" }]
}

如何在没有半引号的情况下传递数据

的javascript

function setData(data){

                map.dataProvider = JSON.parse(data);
                map.validateNow();
            }

0 个答案:

没有答案