Question

我正在进行REST API的测试自动化，而且我是Spring的新手。我有一个非常简单的代码，适用于JSON。

Map<String, String> vars = new HashMap<String, String>();
vars.put("format", "json");
vars.put("address", "1600 Amphitheatre Parkway, Mountain View, CA");
vars.put("sensor", "false");

HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON) ;
headers.setAccept(Arrays.asList(MediaType.APPLICAT ION_JSON));
HttpEntity<String> entity = new HttpEntity<String>(headers);

GeocodeResponsePage response = restTemplate.postForObject(url, entity,  GeocodeResponsePage.class, vars);
System.out.println(response.getStatus());

但是只要我将JSON更改为XML

Map<String, String> vars = new HashMap<String, String>();
vars.put("format", "xml");
vars.put("address", "1600 Amphitheatre Parkway, Mountain View, CA");
vars.put("sensor", "false");

HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_XML);
headers.setAccept(Arrays.asList(MediaType.APPLICATION_XML));
HttpEntity<String> entity = new HttpEntity<String>(headers);

GeocodeResponsePage response = restTemplate.postForObject(url, entity,GeocodeResponsePage.class, vars);
System.out.println(response.getStatus());

我收到以下错误

  org.springframework.web.client.RestClientException : 
  Could not extract response: no suitable HttpMessageConverter found for response 
  type [class com.safenet.GeocodeResponsePage] and content type   
  [application/xml;charset=UTF-8]...

GeocodeResponsePage也很简单。

@JsonIgnoreProperties(ignoreUnknown = true)
public class GeocodeResponsePage
{
 private String status;

 public String getStatus()
 {
    return status;
 }

public void setStatus(String status)
{
   this.status = status;
}
}

如果我使用String作为响应类，它就可以工作。

这是http://maps.googleapis.com/maps/api/geocode/{format}?address={address}&sensor={sensor}的Google网络服务请帮忙。我真的很感激任何帮助。已经花了一整天而且无法使它工作。如果可能，请将代码放入问题解决方案中。提前致谢

没有为响应类型和内容类型找到合适的HttpMessageConverter

0 个答案: