Question

所以我有问题。我正在尝试在这个简单的字符串“Hello World”中更改一个字母所以我正在尝试为这样的内存单元分配值

.section    .text
string:
    .ascii "Hello, world!"
length:
    .quad . -string     #Dot = 'here'

.globl _start       #Make entry point visible to linker
_start:
    movl $4, %eax       #4=write
    movl $1, %ebx       #1=stdout
    movl $string, %ecx
    movl length, %edx
    int $0x80       #Call Operating System



    movl $98,4(%ecx)   #Critical moment why cannot I do this?
    movl $98,string(,%ebx,1)  #cannot do this too ;(


    movl $4, %eax       #4=write
    movl $1, %ebx       #1=stdout
    movl $string, %ecx
    movl length, %edx
    int $0x80 





    movl $0, %ebx       #Make program return syscall exit status
    movl $1, %eax       #1=exit
    int $0x80       #Call System Again

和其他信息我正在x64（linux）工作，并通过linux gas在仿真模式x32中组装它应该没事，TY回复

Answer 1

您已将字符串放入.text部分，该部分为只读。您应该将其放入.data部分（但不要忘记切换回.text以获取程序代码。）

汇编程序SegFail

1 个答案: