Question

我有一张表叫做＃34; PassFailMaster＆＃34;通过PassFail字段为1; 0表示失败。
我需要计算通过次数并失败并在同一行显示它们。我尝试了2个聚合和一个联合，但最终每个测试类型都有2行这是一个数据样本：

CodeName    CodeDesc    TestNumber  PassFail
v1      Vibration   1           0
V1      Vibration   2           0
v1      Vibration   3           1
s1      Shock       4           1
s1      Shock       5           1
s1      Shock       6           0

这是我的查询

SELECT        CodeName, CodeDesc, COUNT(CodeName) AS PassValues, 0 as FailValues
FROM            PassFailMaster
WHERE        (PassFail = 1)
GROUP BY CodeName,  CodeDesc

UNION

SELECT        CodeName, CodeDesc,  0 AS PassValues, COUNT(CodeName) AS FailValues
FROM            PassFailMaster
WHERE        (PassFail = 0)
GROUP BY CodeName,  CodeDesc
ORDER BY CodeName

这里的数据结果如下：

CodeName CodeDesc   PassValues FailValues
s1      Shock       0           1
s1      Shock       2           0
v1      Vibration   0           2
v1      Vibration   1           0

我需要传球和结果的结果没有像这样结束一行。

CodeName CodeDesc PassValues FailValues
s1      Shock       2           1
v1      Vibration   1           2

有什么想法吗？

谢谢 - 迈克

Answer 1

将您的查询用作第二个查询的数据源（即将其用作子查询）：

select 
    codeName, codeDesc, 
    sum(a.passValues) as passValues, sum(a.failValues) as failValues
from
    (
        SELECT
            CodeName, CodeDesc, COUNT(CodeName) AS PassValues, 0 as FailValues
        FROM PassFailMaster
        WHERE (PassFail = 1)
        GROUP BY CodeName,  CodeDesc
        UNION
        SELECT
            CodeName, CodeDesc,  0 AS PassValues, COUNT(CodeName) AS FailValues
        FROM PassFailMaster
        WHERE (PassFail = 0)
        GROUP BY CodeName,  CodeDesc
    ) as a
group by codeName, codeDesc
ORDER BY CodeName

Answer 2

你可以像这样有条件地聚合：

select      codename
            , codedesc
            , sum(case when passfail = 1 then 1 else 0 end) as pass_values
            , sum(case when passfail = 0 then 1 else 0 end) as fail_values
from        passfailmaster
group by    codename
            , codedesc

如何将2个测试的一列聚合到一行的两列中

2 个答案: